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2 years ago

Round the decimals to whole numbers to estimate first, then

Mathematics

1 answer:

nika2105 [10]2 years ago

3 0

Pretty sure the answer would be 16.
Because 7.6 rounds to 8 and 1.4 would round up to 2. Then you multiply 8 & 2 and get 16.

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Please help me I’ll mark you as brainliest! Answer quickly pleaseee

Scrat [10]

Answer:

i need the triangle

Step-by-step explanation:

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2 years ago

Write the number with the same value as 28 tens

Anvisha [2.4K]

The value of 28 tens is basically doing 28 times 10(in case you didn't know). 28 times 10 is 280. So the value of 280 tens is 280.

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2 years ago

Who is up and wants to talk. I can't sleep

Lynna [10]

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1 year ago

Read 2 more answers

Larry has 9 gallons of paint. He uses 10 quarts of paint to paint his kitchen and 3 gallons to paint his living room. How many P

BigorU [14]

He has 9 gallons, he uses 3 gallons for living room and 10 quarts for kitchen

10 quarts = 2.5 gallons

9-3-2.5= 3.5 gallons

3.5 gallons is 28 pints

I hope this helps

3 0

3 years ago

Read 2 more answers

A 500500-gallon tank initially contains 200200 gallons of brine containing 100100 pounds of dissolved salt. brine containing 11

mixer [17]

Let $A(t)$ denote the amount of salt in the tank at time $t$ . We're given that the tank initially holds $A(0)=100$ lbs of salt.

The rate at which salt flows in and out of the tank is given by the relation

$\dfrac{\mathrm dA}{\mathrm dt}=\underbrace{\dfrac{11\text{ lb}}{1\text{ gal}}\times\dfrac{44\text{ gal}}{1\text{ min}}}_{\text{rate in}}-\underbrace{\dfrac{A(t)}{200+(44-11)t}\times\dfrac{11\text{ gal}}{1\text{ min}}}_{\text{rate out}}$
$\implies A'(t)+\dfrac{11}{200+33t}A(t)=484$

Find the integrating factor:

$\mu(t)=\exp\left(\displaystyle\int\frac{11}{200+33t}\,\mathrm dt\right)=(200+33t)^{1/3}$

Distribute $\mu(t)$ along both sides of the ODE:

$(200+33t)^{1/3}A'(t)+11(200+33t)^{-2/3}A(t)=484(200+33t)^{-1/3}$
$\bigg((200+33t)^{1/3}A(t)\bigg)'=484(200+33t)^{-1/3}$
$A(t)=484\displaystyle\int(200+33t)^{-1/3}\,\mathrm dt$
$A(t)=22(200+33t)^{2/3}+C$

Since $A(0)=100$ , we get

$100=22(200)^{2/3}+C\implies C\approx-652.39$

so that the particular solution for $A(t)$ is

$A(t)=22(200+33t)^{2/3}-652.39$

The tank becomes full when the volume of solution in the tank at time $t$ is the same as the total volume of the tank:

$200+(44-11)t=500\implies 33t=300\implies t\approx9.09$

at which point the amount of salt in the solution would be

$A(9.09)\approx733.47\text{ lb}$

4 0

2 years ago