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shusha [124]
3 years ago
13

The total sum of atoms in an object.

Physics
1 answer:
Darina [25.2K]3 years ago
4 0

Answer:

Mass

Explanation:

The total sum of atoms in an object is the mass of the object. There are several ways to quantify the number of atoms in a substance.

  • In chemical calculations, the number of moles is a good representation of the number of atoms contained in a body.
  • Mass is the amount of substances a body has.
  • If we can sum up all the atoms in a substance, one will arrive at the mass of the substance
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The second Law of Thermodynamics states that: A. spontaneous processes are characterized by the overall conversion of order to d
Georgia [21]

Answer:

Spontaneous processes are characterized by the overall conversion of order to disorder.

Explanation:

The second law of thermodynamics states that: A spontaneous process occurs only if there is an increase in entropy of a system and its surroundings.

Entropy, S, is a measure of the randomness or disorder of a system. It is measured in J/Kmol.

The change in entropy, ∆S = ∆H/T

Where ∆H = change in enthalpy, T = Temperature in Kelvin.

For,

I. An endothermic reaction, ∆S = positive (that is, ∆S is greater than zero), there is an increase in entropy, therefore, the reaction is spontaneous.

II. An exothermic reaction, ∆S = negative (that is, ∆S is less than zero) there is a decrease in entropy, so, the reaction is non-spontaneous.

III. A system at equilibrium, ∆S = 0.

Then,

The standard change in entropy of a reaction, ∆So reaction , is the difference in the standard entropies between products and reactants:

∆So reaction = n ∆Soproducts - m ∆Soreactants

Where, = sigma = sum of,

∆ = delta = change in,

n and m = stoichiometric coefficients of the products and reactants respectively.

Furthermore, the entropy of the system and surroundings is referred to as the entropy of the universe.

∆Suniverse = ∆Ssurroundings + ∆Ssystem.

Processes leading to an increase in entropy include melting, heating, vaporization, dissolving.

8 0
3 years ago
What should he do next in order to follow the steps of inquiry?
andrezito [222]

Since he wonders, then according to the formal, methodical procedures of scientific inquiry, he should not go running off and trying stuff before he <em>forms a hypothesis that can be tested.</em>

In his mind, at some point, he should say to himself <em>"Self !  It seems to me that if salt is added to water, it makes the water boil at a higher temperature than pure water does."</em>

And only THEN, with this statement in mind, he's ready to design an experiment to test it.

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How big is the sun ☺️☺️
Klio2033 [76]
The sun is 1.989E30 kg. <em>It's radius is 695, 800 Km.</em>
4 0
3 years ago
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When evaluating data, why is it better to make a graph instead of just looking at the raw data in a table?
marusya05 [52]
In a Data table it doesn’t show increase or decrease while a graph will.
6 0
4 years ago
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A light with frequency of 3.5 x 10^15 Hz is utilized to illuminate the selenium metal (work function 5.11 eV). What will be the
ruslelena [56]

Answer:

The maximum speed of the ejected photoelectrons is 1.815 x 10⁶ m/s.

Explanation:

Given;

frequency of the light, f = 3.5 x 10¹⁵ Hz

work function of the metal, Φ = 5.11 eV

                                              Φ = 5.11 x 1.602 x 10⁻¹⁹ J = 8.186 x 10⁻¹⁹ J

The energy of the incident light is given as sum of maximum kinetic energy and work function of the metal.

E = K.E + Φ

where;

E is the energy of the incident light, calculated as;

E = hf

E = (6.626 x 10⁻³⁴)(3.5 x 10¹⁵)

E = 2.319 x 10⁻¹⁸ J

The maximum kinetic energy of the photoelectrons is calculated as;

K.E = E - Φ

K.E = 2.319 x 10⁻¹⁸ J  - 8.186 x 10⁻¹⁹ J

K.E =  2.319 x 10⁻¹⁸ J - 0.8186 x 10⁻¹⁸ J

K.E = 1.5004 x 10⁻¹⁸J

The maximum speed of the ejected photoelectrons in 10⁶ m/s  is given as;

K.E = ¹/₂mv²

v_{max}^2 = \frac{2K.E}{m} \\\\v_{max}= \sqrt{\frac{2K.E}{m}} \\\\v_{max} =  \sqrt{\frac{2(1.5 \ \times \ 10^{-18})}{(9.11 \ \times \ 10^{-31})}}\\\\v_{max} =1.815 \ \times \ 10^{6} \ m/s

Therefore, the maximum speed of the ejected photon-electrons is 1.815 x 10⁶ m/s.

4 0
3 years ago
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