Ok, so you've got to figure out a force F and you have the speed in which the boxer punches on determinate time and the mass of the sheet of paper.
So based on the formula that says that the Force is equal to the mass multiplied by the acceleration => F=ma.
You look at it and see that you only have mass which is measured on KG so there is no problem.
then you have the acceleration which is measured on meters and is defined by: a = Δv/Δt
So now you can replace the velocity and the time you have there
⇒ a 25m/s / 0.05s
you have computing that ⇒ 50m because the seconds were cancelled out.
and then you plug the meters into the force equation.
F=(0.005kg)(50)
F=0.25N
so the boxer will have a force of 0.25 Newton's.
You answer would be C. Ernest Rutherford.
Answer:
I think is B but I'm not sure
Answer:
c. Both signals are simultaneous.
Explanation:
The speed of light is the same in all frame of reference.
Since an observer inside the ship receives both signals at the same time, then the signals from both flashlight are simultaneously.
To solve this problem we will apply the concepts related to the Doppler Effect, defined as the change in apparent frequency of a wave produced by the relative movement of the source with respect to its observer. Mathematically it can be written as
Here,
= Frequency of the source
= Speed of the sound
= Speed of source
Now the velocity we have that
Then replacing our values,
Therefore the frequency of the observer is 1047.86Hz
