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Alex17521 [72]
4 years ago
9

1. El puente mas largo del mundo es el puente Akashi Kaikyo, en Japón. El puente mide 3910 m de largo y está construido con acer

o. ¿Cuánto mas largo es el puente es un dia caluroso de verano (30°C) qué en un día de invierno (- 5°C)?
Physics
1 answer:
bearhunter [10]4 years ago
8 0

Answer:

It's 1.0000042 times longer in summer than in winter. It represents a 1.6 centimeters difference between seasons.

Explanation:

The linear coefficient of thermal expansion for steel is about 1.2*10^{-7}\°C^{-1}. From the equation of linear thermal expansion, we have:

L_f=L_0(1+\alpha\Delta T)

Taking the winter day as the initial, and the summer day as the final, we can take the relationship between them:

L_{summer}=L_{winter}[1+(1.2*10^{-7}\°C^{-1})(30\°C+5\°C)]\\\\L_{summer}=(1.0000042)L_{winter}

It means that the bridge is 1.0000042 times longer in summer than in winter. If we multiply it by the length of the bridge, we obtain that the difference is of about 1.6 centimeters between the two seasons.

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Which mixture can be separated based on differences in particle size of the components? Check all that apply.
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It’s not Cereal and Milk, carbonated drinks, and smoky air
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3 years ago
A football player, with a mass of 69.0 kg, slides on the ground after being knocked down. At the start of the slide, the player
White raven [17]

Answer:

(a) -472.305  J

(b) 1 m

Explanation:

(a)

Change in mechanical energy equals change in kinetic energy

Kinetic energy is given by0.5mv^{2}

Initial kinetic energy is 0.5\times 69\times 3.7^{2}=472.305 J

Since he finally comes to rest, final kinetic energy is zero because the final velocity is zero

Change in kinetic energy is given by final kinetic energy- initial kinetic energy hence

0-472.305  J=-472.305  J

(b)

From fundamental kinematic equation

v^{2}=u^{2}+2as

Where v and u are final and initial velocities respectively, a is acceleration, s is distance

Making s the subject we obtain

s=\frac {v^{2}-u^{2}}{-2a} but a=\mu g hence

s=\frac {v^{2}-u^{2}}{-2\mu g}=\frac {0^{2}-3.7^{2}}{-2*0.7*9.81}=0.996796272\approx 1 m

7 0
3 years ago
Explain how the thermal energy of a swimming pool compares to the thermal energy of a lake at the same temperature.
astra-53 [7]
There is more thermal energy in the lake because there is more water which is more thermal energy
3 0
3 years ago
What is the magnitude of the electric field at the origin produced by a semi-circular arc of charge = 7.6 μc, twice the charge o
Anna [14]

Orient the semi-circle arc such that it is symmetric with respect to the y-axis. Now, by symmetry, the electric field in the x-direction cancels to zero. So the only thing of interest is the electric field in the y-direction.  


dEy=kp/r^2*sin(a) where k is coulombs constant p is the charge density r is the radius of the arc and a is the angular position of each point on the arc (ranging from 0 to pi. Integrating this renders 2kq/(pi*r^3). Where k is 9*10^9, q is 9.8 uC r is .093 m

I answeared your question can you answear my question pleas

6 0
3 years ago
The peak wavelength of light coming from a giant red star is 660 nm. Calculate the approximate surface temperature of this star
laiz [17]

Answer:

The value is T =260.33 \ F

Explanation:

From the question we are told that  

  The the peak wavelength is  \lambda_p =  660 nm = 660 *10^{-9} \  m

 Generally according to the Wien's displacement law

       \lambda_p *  T =  2.898*10^{-3} \ m \cdot K  

Here T is the approximate surface temperature of this star in K so

       660*10^{-9} *  T =  2.898*10^{-3} \ m \cdot K  

=>    T =  4091 \  K

Converting to Fahrenheit ,

     T = [400 - 273.15 ] * \frac{9}{5} + 32

=>  T =260.33 \ F

5 0
2 years ago
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