Answer:
A bowling ball (8.21rad/s) > A tire (7.94rad/s) > A square (7.75rad/s) > A rock (6.98rad/s) > A top spinning (6.54rad/s)
Explanation:
<u>To rank the angular speed (ω) of the objects, we need first calculate its value for every object:</u>
A bowling ball of radius 12.3cm rotating at 8.21 radians per second:
ω = 8.21 rad/s
A tire of radius 0.321m rotating at 75.8 rpm:
A 6.84cm diameter top spinning at 375 degrees per second:
A square with sides (b) 0.458m long, whose corners are moving with tangential speed (v) 2.51 m/s as it rotates about its center:

A rock on a string, being swung in a circle of radius 0.521 m with a centripetal acceleration (a) of 25.4 m/s²:
<u>Now, the rank of the angular speed of the objects, from highest to lowest is: </u>
A bowling ball (8.21rad/s) > A tire (7.94rad/s) > A square (7.75rad/s) > A rock (6.98rad/s) > A top spinning (6.54rad/s)
I hope it helps you!
Answer:
The intensity is 
Explanation:
From the question we are told that
The intensity of the unpolarized light is 
The angle between the ideal polarizing sheet is 
Generally the intensity of light emerging from the first polarizer is mathematically represented as

substituting values


Then the intensity of incident light emerging from the second polarizer is mathematically represented by Malus law as

substituting values
![I_2 = 2000 * [cos (24.58)]^2](https://tex.z-dn.net/?f=I_2%20%20%3D%202000%20%20%2A%20%5Bcos%20%2824.58%29%5D%5E2)
