All categories

2 years ago

A wave has a wavelength of 125 meters is moving at a speed of 20 m/s. What is it’s frequency?

Physics

1 answer:

Ann [662]2 years ago

4 0

Answer: 0.16Hz

Explanation:

Given that:

wavelength (λ) = 125 meters

speed (V) = 20 m/s

frequency (F) = ?

Recall that frequency is the number of cycles the wave complete in one second. And its value depends on the wavelength and speed of the wave.

So, apply the formula V = F λ

Make F the subject formula

F = V / λ

F = 20 m/s / 125 meters

F = 0.16 Hz

Thus, the frequency of the wave is 0.16 Hertz.

You might be interested in

A car going 50 miles/hr accelerates to pass a truck. 5 seconds later the car is going 80 miles/hr. What is the acceleration of t

mariarad [96]

It would be 6 mph/s 11

5 0

2 years ago

After you cross the finish line, you slow down and come to a stop, breathing hard. It takes you 10 seconds to come to a stop. Wh

Otrada [13]

Acceleration = (change in speed) / (time for the change)

Acceleration = -- (speed as you crossed the finish line) / (10 seconds)

4 0

2 years ago

In order for work to be done, what must be true?

Amiraneli [1.4K]

Answer:

option c

Explanation:

Work is said to be done when a force moves a body over a distance, in the direction of force applied.

Work done = force x distance (in the direction of the force)

Therefore work = force x displacement

As displacement is distance in a specific or specified direction.

I hope this was helpful, Please mark as brainliest

5 0

3 years ago

a bungee jumper of mass 50 kg jumps from a bridge using a 10 m long cord which can be approximated as a spring with spring const

Maslowich

Answer:

25.95 m

Explanation:

m = mass of the bungee jumper = 50 kg

k = spring constant of the cord = 100 N/m

x = stretch of the cord

L = length of the cord = 10 m

h = height dropped by the bungee jumper = L + x = 10 + x

Using conservation of energy

Spring potential energy = gravitational potential energy

(0.5) k x² = mg h

(0.5) (100) x² = (50) (9.8) (10 + x)

x = 15.95 m

d = distance traveled below the bridge

d = L + x

d = 10 + 15.95

d = 25.95 m

3 0

3 years ago

A box sits on the back of a flatbed truck. If the coefficient of static friction between the box and the truck bed is μs = 0.400

slava [35]

Answer:

28,699m

Explanation:

The force to make the box move should be μs.N=μs.m.g=m.|a|

then,

|a|=μs.g

Being

μs coefficient of static friction,

N the force made by the truck on the box caused by the gravity force,

m the mass,

g the acceleration of gravity

and a the acceleration of the truck.

$x = v \times t + \frac{1}{2} \times a \times {t}^{2}$

as the truck is stopping, the acceleration is negative. then,

$x = v \times t - \frac{1}{2} \times |a| \times {t}^{2}$

$|a| = v \div t \\ t = v \div |a|$

$x = v \times (v \div |a| ) - \frac{1}{2} \times |a| \times {(v \div |a|)}^{2}$

$x = v \times (v \div μs.g ) - \frac{1}{2} \times |a| \times {(v \div μs.g)}^{2}$

$x = \frac{{v}^{2}}{μs \times g} - \frac{1}{2} \times \frac{{v}^{2}}{μs \times g} \\ x = \frac{1}{2} \times \frac{{v}^{2}}{μs \times g} \\ x = 0.5 \times \frac{{(15m/s) }^{2} }{0.4 \times 9.8m/ {s}^{2} } = 28.699m$

28,699m

7 0

2 years ago