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AlexFokin [52]
3 years ago
7

There is a cookie jar in Julio's kitchen filled with 7 cookies. His mother bakes some more cookies. Now there are 14 cookies. Ho

w many cookies did Julio's mother bake.
Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
4 0
The Answer is 7 cookies because she had 7 cookies filled in the jar and after making 7 more it becomes 14 so
Also 7+7=14
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Drew is driving out of state to go to a theme park. The total distance he is driving is 500.34 miles. He has driven 0.45 of the
alexgriva [62]

The calculation is not reasonable, because 0.45 is less tha 1/2 ( 0.50) and what he has for an answer is half the distance ( 250.17 is 1/2 of 500.34).

To find actual mileage, multiply by 0.45:

500.34 x 0.45 = 225.153 miles.

Round the answer as needed.

5 0
3 years ago
48 inches<br> 32 inches<br> 18. Inches <br><br><br> What is the area of the building front?
jarptica [38.1K]
48 inches is the area in the front of the building
7 0
2 years ago
A recipe uses 5 cups of water for<br> every 3 cups of flour?
Lerok [7]

Answer:

There's no context for a conclusion.

Step-by-step explanation:

Comment when you've edited the question.

6 0
3 years ago
The perimeter of a rectangular field is 328 yards. If the length of the field is 89 yards, what is its width?
miv72 [106K]

<u>Set up an equation based on the information given</u>

89 + 89 + x + x = 328

<u>Combine like terms</u>

89 + 89 = 178

x + x = 2x

2x + 178 = 328

<u>Solve</u>

2x + 178 = 328

328 - 178 = 150

2x = 150

x = 75

Answer

The width of the rectangular field is 75 yards.

7 0
3 years ago
(10.02)
melisa1 [442]

Answer:

sin O=\dfrac{3\sqrt{13}}{13}\\cos O=\dfrac{2\sqrt{13}}{13}\\tan O=\dfrac{3}{2}

Step-by-step explanation:

If the point (2,3) is on the terminal side of an angle in standard position.

Adjacent of O, x=2,

Opposite of O, y=3

Next, we determine the hypotenuse, r using Pythagoras Theorem.

Hypotenuse =\sqrt{Opposite^2+Adjacent^2} \\r=\sqrt{3^2+2^2} \\r=\sqrt{13}

Therefore:

sin O=\dfrac{Opposite}{Hypotenuse} \\sin O=\dfrac{3}{\sqrt{13}} \\$Rationalizing\\sin O=\dfrac{3\sqrt{13}}{13}

cos O=\dfrac{Adjacent}{Hypotenuse} \\cos O=\dfrac{2}{\sqrt{13}} \\$Rationalizing\\cos O=\dfrac{2\sqrt{13}}{13}

Tan O=\dfrac{Opposite}{Adjacent} \\tan O=\dfrac{3}{2}

4 0
3 years ago
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