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Shalnov [3]
3 years ago
15

Determine whether the conditional and its converse are both true. If both are true, combine them as a biconditional. If either i

s false, provide a counterexample. If an angle is a right angle, its measure is 90. If an angle measure is 90, the angle is a right angle. Both statements are true. An angle is a right angle if and only if its measure is 90. Both statements are true. The measure of an angle is 90 if and only if it is not a right angle. One statement is false. If an angle is a right angle, its measure may be 180. One statement is false. If an angle measure is 90, the angle may be an obtuse angle.
Mathematics
2 answers:
Marina CMI [18]3 years ago
6 0
If an angle is a right angle, its measure is 90.
If an angle measure is 90, the angle is a right angle.

The answer is:
Both statements are true.

This is the biconditional.
An angle is a right angle if and only if its measure is 90°.

Other types of angles: Acute angle - less than 90° Obtuse angle - more than 90° but less than 180°. Straight angle - exactly 180° Reflex angle - more than 180°
Nimfa-mama [501]3 years ago
5 0

Answer: The answer is (B) "both statements are true. An angle is a right angle if and only if it's measure is 90°."

Step-by-step explanation: The given statements are

If an angle is right angle, it's measure is 90°.

If the measure of an angle is 90°, then it is a right angle.

Both the statements are true. We can combine them as a unconditional as follows:

An angle is a right angle if an only if it's measure is 90°.

Hence, (B) is the correct option.

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Help<br> me please asap
enot [183]

Answer:

first one:

Area of a circle = π*r²

diameter (they gave) = 30ft

radius = diameter/2 = 15ft

π*15²= 706.85834705770347865409476123789‬

to nearest tenth= 706.9 ft

second question:

circumference = 2*π*r or d(diameter)*π

diameter = 30ft

30*π = circumference = 94.247779607693797153879301498385‬

in terms of π = 30π

4 0
3 years ago
A spinner is divided into four equal sections labeled A, B, C, D. After 50 trials, the spinner landed on A 14 times, on B 13 tim
svp [43]

Answer:

17/25

Step-by-step explanation:

P(not red)=Number of Skittles Not Red/Total Number of Skittles

6 0
2 years ago
The surface area of a right circular cone of radius r and height h is S = πr√ r 2 + h 2 , and its volume is V = 1 3 πr2h. What i
kirill115 [55]

Answer:

Required largest volume is 0.407114 unit.

Step-by-step explanation:

Given surface area of a right circular cone of radious r and height h is,

S=\pi r\sqrt{r^2+h^2}

and volume,

V=\frac{1}{3}\pi r^2 h

To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,

f(r,h)=\frac{1}{3}\pi r^2 h

subject to,

g(r,h)=\pi r\sqrt{r^2+h^2}=8\hfill (1)

We know for maximum volume r\neq 0. So let \lambda be the Lagranges multipliers be such that,

f_r=\lambda g_r

\implies \frac{2}{3}\pi r h=\lambda (\pi \sqrt{r^2+h^2}+\frac{\pi r^2}{\sqrt{r^2+h^2}})

\implies \frac{2}{3}r h= \lambda (\sqrt{r^2+h^2}+\frac{ r^2}{\sqrt{r^2+h^2}})\hfill (2)

And,

f_h=\lambda g_h

\implies \frac{1}{3}\pi r^2=\lambda \frac{\pi rh}{\sqrt{r^2+h^2}}

\implies \lambda=\frac{r\sqrt{r^2+h^2}}{3h}\hfill (3)

Substitute (3) in (2) we get,

\frac{2}{3}rh=\frac{r\sqrt{R^2+h^2}}{3h}(\sqrt{R^2+h^2+}+\frac{r^2}{\sqrt{r^2+h^2}})

\implies \frac{2}{3}rh=\frac{r}{3h}(2r^2+h^2)

\implies h^2=2r^2

Substitute this value in (1) we get,

\pi r\sqrt{h^2+r^2}=8

\implies \pi r \sqrt{2r^2+r^2}=8

\implies r=\sqrt{\frac{8}{\pi\sqrt{3}}}\equiv 1.21252

Then,

h=\sqrt{2}(1.21252)\equiv 1.71476

Hence largest volume,

V=\frac{1}{3}\times \pi \times\frac{\pi}{8\sqrt{3}}\times 1.71476=0.407114

3 0
3 years ago
Find m (2x+14)<br> (X+7)
LekaFEV [45]

Answer:

=

Step-by-step explanation:

Ⓗⓘ ⓣⓗⓔⓡⓔ

Well, assuming m of angle ABD is 90 degrees, then you would add and then solve.

2x+14+x+7=90

3x+21=90

3x=69

=

(っ◔◡◔)っ ♥ Hope this helped! Have a great day! :) ♥

, !

4 0
3 years ago
Suppose you have a 6-face unfair dice with numbers 1,2,3,4,5,6 on each of its faces. If the probability distribution of throwing
kotegsom [21]

Answer:

D is correct

Step-by-step explanation:

Here, we want to select which of the options is correct.

The correct option is the option D

Since the die is unfair, we expect that the probability of each of the numbers turning up

will not be equal.

However, we should also expect that if we add the chances of all the numbers occurring together, then the total probability should be equal to 1. But this does not work in this case;

In this case, adding all the probabilities together, we have;

1/12 + 1/12 + 1/12 + 1/12 + 1/12 + 1/2

= 5(1/12) + 1/2 = 5/12 + 1/2 = 11/12

11/12 is not equal to 1 and thus the probability distribution cannot be correct

4 0
3 years ago
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