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nikitadnepr [17]
2 years ago
9

If a compound has a molar mass of 180 g/mol and its empirical formula is CH2O, what is its molecular formula? CH2O C2H4O2 C6H12O

6 C12H22O11
Chemistry
2 answers:
irinina [24]2 years ago
3 0

Its molecular formula : C₆H₁₂O₆

<h3>Further explanation  </h3>

The empirical formula(EF) is the smallest comparison of atoms of compound forming elements.  

A molecular formula(MF) is a formula that shows the number of atomic elements that make up a compound.  

(EF) n = MF

its empirical formula is CH₂O

CH₂O : 12+2+16=30

\tt [30]n=180\rightarrow n=6\\\\(CH_2O]_6=C_6H_{12}O_6

IgorC [24]2 years ago
3 0

Answer:

C. C6H12O6

Explanation:

For edge(:

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He (Helium) is _________ atomic molecule.
babunello [35]

Answer:

Monatomic molecule

Explanation:

Each helium atom has 2 electrons, which is already the maximum no. of electrons that can fit in the first electron shell. When the outermost electron shell is full (2 for the first layer, 8 for others), the atom is stable.

Helium atom itself is already stable, so it doesn't need to combine with another helium atom to form a molecule, hence we call it monatomic.

8 0
3 years ago
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The absorbance of an equilibrium mixture containing FeSCN2 was measured at 447 nm and found to be 0.347. What is the equilibrium
Ksenya-84 [330]

Answer:

The concentration is C = 1.11 mol/L

Explanation:

From the question we are told that

     The absorbance is  A = 0.347

       The length is  l =  447 nm  =  447 *10^{-7} \ cm

     

Generally absorbance is mathematically represented as

        A =  \epsilon*  C * l

where \epsilon is the molar absorptivity of  FeSCN2  with a value \epsilon  =  7.0*10^3 L/cm/mol

 and  C is the equilibrium concentration of FeSCN2

So  

       C = \frac{A}{\epsilon *  l  }

substituting values

        C = \frac{0.347}{7.0*10^{3} *  447 *10^{-7}  }

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5 0
3 years ago
N=4 has how many orbitals?
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Answer:

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5 0
3 years ago
If you start with 89.3 g no(g) and 28.6 g h2(g), find the theoretical yield of ammonia.
Tatiana [17]
Balanced equation: 
<span>2 NO + 5 H2 ------> 2 NH3 + 2 H2O
 </span>
<span>2 moles NO react with 5 moles H2 to produce 2 moles NH3
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<span>86.3g NO = 86.3/30.00 = 2.877 moles of NO </span>

<span>This will require: 2.877*5 / 2 = 7.192 moles of H2 </span>

<span>Molar mass of H2 = 2 g/mol </span>
<span>25.6g H2 = 25.6/2 = 12.7 mol H2. </span>
<span>You have excess H2 means the NO is limiting </span>

<span>From the balanced equation: </span>
<span>2 moles of NO will produce 2 moles of NH3 </span>
<span>2.877 moles of NO will produce 2.877 moles of NH3 </span>

<span>Molar mass NH3 = 17g/mol </span>
<span>Mass NH3 produced = 2.877 * 17 = 48.91g 

Hence the yield is = 48.91 g ~ 49 g</span>
3 0
3 years ago
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................................................................................................................................
viktelen [127]

Answer:

HmmmmmmmmmmI think the answer is 69

3 0
3 years ago
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