Question

Kc is 1.67 x 10^20 at 25 °C for the formation of iron(III) oxalate complex ion:

Answer 1

Answer:

$n_{C_2O_4^{2-}}=1.59mol C_2O_4^{2-}$

Explanation:

Hello there!

In this case, according to the given information and chemical equation, it turns out possible for us to calculate the moles of C2O4^2- by firstly setting up the equilibrium expression:

$Kc=\frac{[[Fe(C_2O_4)_3]^{3-}]}{[Fe^{3+}][C_2O_4^{2-}]^3}$

However, according to the question, we just need to apply the given 1:3 mole ratio in the chemical reaction, of iron (III) ions to oxalate ions to obtain:

$n_{C_2O_4^{2-}}=0.53molFe^{3+}*\frac{3molC_2O_4^{2-}}{1molFe^{3+}}=1.59mol C_2O_4^{2-}$

Regards!