Which element of the third period had the highest first ionization energy?
1 answer:
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<u>Answer:</u> The mass of water that must be reacted is 56.28 grams.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
....(1)
Given mass of oxygen = 50 g
Molar mass of oxygen = 32.00 g/mol
Putting values in equation 1, we get:
For the given chemical equation:
By Stoichiometry of the reaction:
1 mole of oxygen is produced when 2 moles of water is reacted.
So, 1.5625 moles of oxygen is produced when = of water is reacted.
To calculate the mass of water, we use equation 1:
Moles of water = 3.125 moles
Molar mass of water = 18.01 g/mol
Putting values in equation 1, we get:
Hence, the mass of water that must be reacted is 56.28 grams.