For the purpose we will here use t<span>he ideal gas law:
p</span>×V=n×R×<span>T
V= </span><span>5.0 L
T= </span><span>373K
p= </span><span>203kPa
</span><span>
R is </span> universal gas constant, and its value is 8.314 J/mol×<span>K
</span>
Now when we have all necessary date we can calculate the number of moles:
n=p×V/R×T
n= 203 x 5 / 8.314 x 373 = 0.33 mole
A polar molecule is when the arrangement of the atoms in molecules are unequal, so one end of the molecule has a positive charge, and the other end has a negative charge.
Answer:
1,869.97 grams of Be(NO3)2
Explanation:
Be(NO3)2 = Be N2 O6
Be=9.012182g/mole
N2=28.0134g/mole
O6=96g/mole
therefore Be(NO3)2 gives you 187.56g in one mole
so 9.97 moles means there is 9.97 times more
9.97mole Be(NO3)2 * 187.56g Be(NO3)2/1mole Be(NO3)2 = 1,869.97g of Be(NO3)2
Answer:
3.94 × 10³ g
Explanation:
Step 1: Write the neutralization reaction
HClO₃ + NaOH = NaClO₃ + H₂O
Step 2: Calculate the moles of chloric acid that react
25.5 L of 3.86 M chloric acid is to be neutralized. The reacting moles are:
Step 3: Calculate the required moles of sodium hydroxide
The molar ratio of HClO₃ to NaOH is 1:1. Then, the reacting moles of NaOH are 98.4 moles.
Step 4: Calculate the mass of sodium hydroxide corresponding to 98.4 moles
The molar mass of NaOH is 40.00 g/mol.
