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3 years ago

CzHs + 02-> CO2+ _H20 * I need help ASAP PLSSS

Chemistry

1 answer:

Alex777 [14]3 years ago

8 0

Answer:

2,7,4,6

Explanation:

atoms at the left side should be equal to that of right for an equation to be balanced. so the answer is the final one

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What is the mole fraction of acetic acid in a solution containing 2 moles of vinegar and 3 moles of water? A. 2 B. 3 C. 0.4 D. 0

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Answer:

C. 0.4.

Explanation:

∵ mole fraction of acetic acid (X acetic acid) = (no. of moles acetic acid)/(total no. of moles) = (no. of moles acetic acid)/(no. of moles of acetic acid + no. of moles of water).

- no. of moles of acetic acid = 2, no. of moles of water = 3.

- Total no. of moles = no. of moles of acetic acid + no. of moles of water = 2 + 3 = 5.

∴ mole fraction of acetic acid (X acetic acid) = (no. of moles acetic acid)/(total no. of moles) = (2)/(5) = 0.4.

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3 years ago

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Which group of elements shares characteristics with both metals and nonmetals?

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The answer to your question is,

Metalloids. They are a mix of elements that are both metals and non-metals in one.

-Mabel <3

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3 years ago

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Which is bigger in width mm,cm,m,km

Kay [80]

Km is the biggest measure in width (even if there are bigger measures like Mm, Gm, Tm).

1 Km = 1000 m, 100000 cm and 1000000 mm

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Solid aluminum and gaseous oxygen read in a combination reaction to produce aluminum oxide. 4Al(s) + 3O_2(g) rightarrow 2Al_2O_3

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Answer:

4.7 g. Option 5 is the right one.

Explanation:

4Al(s) + 3O₂ (g) ⇄ 2Al₂O₃ (s)

We convert the mass of reactants to moles, in order to determine the limiting.

2.5 g Al / 26.98 g/mol → 0.092 moles of Al

2.5 g O₂ / 32g/mol → 0.078 moles of O₂

Ratio is 4:3. 4 moles of Al react with 3 moles of O₂

Then, 0.092 moles of O₂ would react with (0.092 . 3)/ 4 = 0.069 moles O₂

We have 0.078 moles of O₂ and we need 0.069 moles, the oxygen is the limiting in excess. Therefore the Al is the limiting reactant.

Ratio is 4:2. 4 moles of Al, can produce 2 moles of Al₂O₃

Then, 0.092 moles of Al would produce (0.092 .2) / 4 = 0.046 moles

If we convert the moles to mass, we find the anwer:

0.046 mol . 101.96 g/mol = 4.69 g

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3 years ago

When solutions of silver nitrate and sodium chloride are mixed, a precipitation reaction occurs. What mass of precipitate can be

Bas_tet [7]

Explanation:

The given precipitation reaction will be as follows.

$AgNO_{3}(aq) + NaCl(aq) \rightarrow AgCl(s) + NaNO_{3}(aq)$

Here, AgCl is the precipitate which is formed.

It is known that molarity is the number of moles present in a liter of solution.

Mathematically, Molarity = $\frac{\text{no. of moles}}{\text{volume in liter}}$

It is given that volume is 1.14 L and molarity is 0.269 M. Therefore, calculate number of moles as follows.

Molarity = $\frac{\text{no. of moles}}{\text{volume in liter}}$

0.269 M = $\frac{\text{no. of moles}}{1.14 L}$

no. of moles = 0.306 mol

As molar mass of AgCl is 143.32 g/mol. Also, relation between number of moles and mass is as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

0.307 mol = $\frac{mass}{143.32 g/mol}$

mass = 43.99 g

Thus, we can conclude that mass of precipitate produced is 43.99 g.

8 0

3 years ago

CzHs + __02-> __CO2+ _H20 * I need help ASAP PLSSS

CzHs + 02-> CO2+ _H20 * I need help ASAP PLSSS