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butalik [34]
3 years ago
8

Explain why phosphorus has a low melting point.

Chemistry
2 answers:
Minchanka [31]3 years ago
8 0

Answer:

Phosphorus has a low melting point because the intramolecular forces holding it together is London Dispersion Forces.

Explanation:

London Dispersion Forces (LDF) are the weakest intramolecular forces. You don't need to break the covalent bonds, but rather the Van Der Waals' Forces. If LDF are the weakest forces, then the melting point is low.

Dima020 [189]3 years ago
7 0

Answer:

because the intramolecular forces holding it together is London Dispersion Forces.

Explanation:

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Rb has larger radius.

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Why is the earth often referred to as the blue planet
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Most of the surface of the earth is covered with water and looks blue from space.

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Can I please Get Help with this question ‍♂️ ?
Nitella [24]

Answer:

Mg(NO4)2 is 180.3 g/mol

Explanation:

First find the substance formula.

Magnesium Nitrate.

Magnesium is a +2 charge.

Nitrate is a -1 charge.

So to balance the chemical formula,

We need 1 magnesium atom for every nitrate atom.

2(1) + 1(-2) = 0

So the substance formula is Mg(NO4)2.

Now find the molar mass of Mg(NO4)2.

Mg = 24.3 amu

N = 14.0 amu

O = 16.0 amu

They are three nitrogen and twelve oxygen atoms.

So you do this: 24.3 + 14.0(2) + 16.0(8) = 180.3 g/mol

So the molar is mass is 180.3 g/mol.

The final answer is Mg(NO4)2 is 180.3 g/mol

Hope it helped!

7 0
3 years ago
A liquid has a _____.
guajiro [1.7K]

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definite volume

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2 years ago
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An iron(iii) sulfate hydrate is 18.4% water. What is the formula of the hydrate? What is the name of the hydrate?
aleksley [76]

Answer:- Formula of the hydrate is Fe_2(SO_4)_3.5H_2O and it's name is Iron(III)sulfate pentahydrate.

Solution:- As per the given information, there is 18.4% water in the hydrate. If we assume the mass of the hydrate as 100 grams then there would be 18.4 grams of water and 81.6 grams of Iron(III)sulfate present in the hydrate.

Molar mass for Iron(III)sulfate is 399.88 gram per mol and the molar mass for water is 18.02 gram per mol.

We will calculate the moles of Iron(III)sulfate and water present in the compound on dividing their grams by their molar masses as:

81.6gFe_2(SO_4)_3(\frac{1mol}{399.88g})

= 0.204molFe_2(SO_4)_3

18.4gH_2O(\frac{1mol}{18.02g})

= 1.02molH_2O

Now, the next step is to calculate the mol ratio and for this we divide the moles of each by the least one of them means whose moles are less. Here, the moles of Iron(III)sulfate are less than moles of water. So, we divide the moles of each by 0.204.

Fe_2(SO_4)_3=\frac{0.204}{0.204}  = 1

H_2O=\frac{1.02}{0.204} = 5

There is 1:5 mol ratio between Iron(III)sulfate and water. So, the formula of the hydrate is Fe_2(SO_4)_3.5H_2O and the name of the hydrate is Iron(III)sulfate pentahydrate.


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2 years ago
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