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riadik2000 [5.3K]
3 years ago
14

What is the empirical formula of an oxide of nitrogen containing 63.61% by mass of nitrogen and 36.69% by mass of oxygen?

Chemistry
1 answer:
katen-ka-za [31]3 years ago
8 0

Answer:

D. N₂O

Explanation:

Let's assume we have 100 g of the compound.  That means it consists of 63.61 grams of nitrogen and 36.69 grams of oxygen.

Converting masses to moles:

63.61 g N × (1 mol N / 14.01 g N) = 4.540 mol N

36.69 g O × (1 mol O / 16.00 g O) = 2.293 mol O

Normalize by dividing by the smallest:

4.540 / 2.293 = 1.980 mol N

2.293 / 2.293 = 1.000 mol O

So there is approximately twice as many N atoms as O atoms.  The empirical formula is therefore N₂O.

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Which of the following sets of characteristics describe what we know about the inner planets?
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The sets of characteristics describe what we know about the inner planets is that have rocky surfaces, no rings, and few or no moons. The answer is letter C. Also, they are smaller in sizes compared to the outer planets. The rest of the choices are characteristics of the outer planets.

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3 years ago
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Is Helium a compound,element, or.mixture
dusya [7]

Answer:

element

Explanation:

we know that helium is a pure substance although helium atoms are sometimes mixed with their isotopes it is still the same element. since there is no other element combined with helium this makes it an element.

5 0
3 years ago
Butane, C4H10 burns in oxygen. How many grams of water vapor, H2O, are produced by the combustion of 580 grams of butane at stan
zepelin [54]

Answer:

The answer to your question is 900 g of water vapor

Explanation:

Data

mass of H₂O = ?

mass of butane = 580 g

Balanced chemical reaction

             2C₄H₁₀ + 13O₂  ⇒  8CO₂  +  10H₂O

Process

1.- Calculate the molar weight of butane and water

Butane (C₄H₁₀) = 2[(12 x 4) + (1 x 10)]

                         = 2[48 + 10]

                         = 2[58]

                         = 116 g

Water (H₂O) = 10[(1 x 2) + (1 x 16)]

                    = 10[2 + 16]

                    = 10[18]

                    = 180 g

2.- Use proportions and cross multiplication to find the mass of water vapor

             116 g of butane ------------- 180 g of water

             580 g of butane  ----------  x

                x = (580 x 180) / 116

                x = 900 g of water vapor

3 0
3 years ago
Methane is the main component of natural gas. Using the given reaction enthalpy, calculate the heat energy produced by the combu
SVETLANKA909090 [29]

Answer: The heat energy produced is 53831.25KJ

Explanation:

METHANE is the main component of natural gas. It can undergo combustion reaction in air with a bright blue flame to produce carbondioxide and water. The heat of reaction (enthalpy) is negative because heat is absorbed during the chemical reaction. To calculate the heat energy produced by the combustion of one kilogram (1 kg) of methane the following steps are taken:

Molecular mass of methane =16 gm/mol.

So moles of 1 kg methane =

Given mass of methane ÷ molecular weight of methane

But the given mass = 1kg = 1000g

Therefore,

moles of 1000g methane = 1000÷16

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Hence, energy evolved = (moles of methane) × (heat of combustion)

Therefore,

heat energy produced= 62.5 × (-861.3kj)

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7 0
3 years ago
If 180 grams of potassium iodide is dissolved in 100 cm3 of water at 30oC, a(n) _______________ solution is formed.
olga nikolaevna [1]

Super saturated solution is formed.

<u>Explanation:</u>

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  • Unsaturated solution is a solution with lesser amount of solute than its solubility at equilibrium.
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The solubility of KI at 30°C is 153 g / 100 ml. Here 180 g of KI in 100 ml of water at 30°C is given, which has more solute than required, so it is super saturated solution.

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3 years ago
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