An electric field travels away from a <u>positive charge</u> and toward a <u>negative charge</u>.
<h3>
What is electric field?</h3>
Electric field is the region of space where the impact of electric force is felt.
The electrostatic field is always directed away from positive charges and toward negative charges, and, field lines must go away from positive charges and toward negative ones.
Thus, an electric field travels away from a positive charge and toward a negative charge.
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Answer:
Dissociation Equations Worksheet
Write balanced chemical equations to represent the slight dissociation or the
complete dissociation for 1 mole of the following compounds. In the case of slight
dissociation use a double arrow and for complete dissociation use a single arrow.
Include phase notation in the equations.
1) silver chloride
2) sodium acetate
3) ammonium sulfate
4) calcium carbonate
5) potassium carbonate
6) sodium hydroxide
7) silver chlorate
8) iron(II) sulfate
9) lead(II) phosphate
10) lead(II) chromate
11) iron(III) chloride
12) calcium nitrate
13) iron(III) oxide
14) copper(II) sulfate
15) mercury(II) sulfide
16) zinc chloride
17) lead(II) acetate
18) aluminum phosphate
Solutions
1) AgCl(s) ↔ Ag+
(aq) + Cl-
(aq)
2) NaC2H3O2(s) Æ Na+
(aq) + C2H3O2
-
(aq)
3) (NH4)2SO4(s) Æ 2NH4
+
(aq) + SO4
2-(aq)
4) CaCO3(s) ↔ Ca2+(aq) + CO3
2-(aq)
5) K2CO3(s) Æ 2K+
(aq) + CO3
2-(aq)
6) NaOH(s) Æ Na+
(aq) + OH-
(aq)
7) AgClO3(s) Æ Ag+
(aq) + ClO3
-
(aq)
8) FeSO4(s) Æ Fe2+(aq) + SO4
2-(aq)
9) Pb3(PO4)2(s) ↔ 3Pb2+(aq) + 2PO4
3-(aq)
10) PbCrO4(s) ↔ Pb2+(aq) + CrO4
2-(aq)
11) FeCl3(s) Æ Fe3+(aq) + 3Cl-
(aq)
12) Ca(NO3)2(s) Æ Ca2+(aq) + 2NO3
-
(aq)
13) Fe2O3(s) ↔ 2Fe3+(aq) + 3O2-(aq)
14) CuSO4(s) Æ Cu2+(aq) + SO4
2-(aq)
15) HgS(s) ↔ Hg2+(aq) + S2-(aq)
16) ZnCl2(s) Æ Zn2+(aq) + 2Cl-
(aq)
17) Pb(C2H3O2)2(s) Æ Pb2+(aq) + C2H3O2
-
(aq)
18) AlPO4(s) ↔ Al3+(aq) + PO4
3-(aq)
Explanation:
3AgNO₃ + Na₃PO₄ → Ag₃PO₄ + 3NaNO₃
Explanation:
AgNO₃+Na₃(PO₄) → Ag₃(PO₄) + NaNO₃
To balance this chemical equation, we can adopt a simple mathematical approach through which we can establish simple and solvable algebraic equations.
aAgNO₃ + bNa₃PO₄ → cAg₃PO₄ + dNaNO₃
a, b, c and d are the coefficients needed to balance the equation.
Conserving Ag: a = 3c
N: a = d
O: 2a + 4b = 4c + 2d
Na: 3b = d
P: b = c
let a = 1; d = 1
b =
c =
Multiplying through by 3:
a = 3, b = 1, c = 1 and d = 3
3AgNO₃ + Na₃PO₄ → Ag₃PO₄ + 3NaNO₃
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Balanced equation
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From the calculations, the pH of the buffer is 3.1.
<h3>What is the pH of the buffer solution?</h3>
The Henderson-Hasselbach equation comes in handy when we deal with the pH of a buffer solution. From that equation;
pH = pKa + log[(salt/acid]
Amount of the salt = 25/1000 * 0.50 M = 0.0125 moles
Amount of the acid = 75/1000 * 1.00 M = 0.075 moles
Total volume = ( 25 + 75)/1000 = 0.1 L
Molarity of salt = 0.0125 moles/0.1 L = 0.125 M
Molarity of the acid = 0.075 moles/0.1 L = 0.75 M
Given that the pKa of lactic acid is 3.86
pH = 3.86 + log( 0.125/0.75)
pH = 3.1
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I think, the question should by:
When does quenching occur in a chemiluminescence reaction?
Quenching is a process that decreases the fluorescence intensity of any compound while chemiluminescence refers to emission of cold light due to a chemical reaction. Quenching of fluorophore occurs in a chemiluminescence reaction when the fluorescence of the fluorophore is quenched that leads to the decrease in the intensity of the fluorescence.
In terms of energy transfer, quenching occurs when loss of excitation energy of the molecule takes place in a chemiluminescence reaction.