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Serjik [45]
3 years ago
15

What is the percent of SO2 in H2SO4? Help Please

Chemistry
1 answer:
Yakvenalex [24]3 years ago
3 0

The percent of SO₂ in H₂SO₄ : 65.3%

<h3>Further explanation </h3>

Proust states the Comparative Law that compounds are formed from elements with the same Mass Comparison so that compounds have a fixed composition of elements

%Mass A in AxBy =  

\tt \dfrac{x.Ar~A}{MW~A_xB_y}\times 100\%  

For SO₂ in H₂SO₄ :

MW SO₂ = 32 + 2.16=64 g/mol

MW H₂SO₄ =2.1+32+4.16=98 g/mol

The percent of SO₂ :

\tt \dfrac{64}{98}\times 100\%=65.3\%

 

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Which member of each pair is more soluble in water? Why?<br> (a) CH₃CH₂OCH₂CH₃(l) or CH₃CH₂OCH₂(g)
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CH₃CH₂OCH₂ is more soluble in water because it has shorter hydrocarbon chain.

<h3>What is hydrocarbon?</h3>

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7 0
1 year ago
A certain substance X has a normal freezing point of -6.4 C and a molal freezing point depression constant Kf= 3.96 degrees C.kg
Brut [27]

Answer:  1.0\times 10^2g

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=(-6.4-(13.6))^0C=7.2^0C = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte like urea)

K_f = freezing point constant = 3.96^0C/m

m= molality

\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}}\times \text{weight of solvent in kg}}

Weight of solvent (X)= 950 g = 0.95 kg  

Molar mass of non electrolyte (urea) = 60.06 g/mol

Mass of non electrolyte (urea) added = ?

7.2=1\times 3.96\times \frac{xg}{60.06 g/mol\times 0.95kg}

x=1.0\times 10^2g

Thus 1.0\times 10^2g urea was dissolved.

8 0
3 years ago
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