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Viefleur [7K]
3 years ago
13

Thomson's experiments were significant in that they questioned

Chemistry
2 answers:
castortr0y [4]3 years ago
8 0
The answer is letter D
Vlad [161]3 years ago
6 0

Answer:

The correct answer is option B.

Explanation:

J.J Thomson was an English physicist who had given the plum pudding model of the atom in 1904. In which he described about the existence of two subatomic particles which are protons (positive particles) and electrons (negative particles).

In his model atom was considered to be a pudding or bed of positive charge in which negative particles are present same as as plum on the pudding.

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2 years ago
Please answer quickly ​
Stolb23 [73]
Inherited it from his grandfather
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2 years ago
A 365 L balloon is blown up inside at 283 K. It is then taken outside in the hot sun and Heated to 300K. What is the new volume?
asambeis [7]

V₁ = initial Volume of the balloon after it is blown up = 365 L

V₂ = new Volume of the balloon after it is taken outside = ?

T₁ = initial temperature of the balloon = 283 K

T₂ = new temperature of the balloon = 300 K

using the equation

V₁/V₂ = T₁/T₂

365/V₂ = 283/300

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6 0
3 years ago
A generic weak acid with formula HA has a Ka = 2.76 x 10-8. Calculate the Kb for the conjugate base of the acid.
Reika [66]

Answer:

3.62x10⁻⁷ = Kb

Explanation:

The acid equilibrium of a weak acid, HX, is:

HX + H₂O ⇄ X⁻ + H₃O⁺

Where Ka = [X⁻] [H₃O⁺] / [HX]

And basic equilibrium of the conjugate base, is:

X⁻ + H₂O ⇄ OH⁻ + HX

Where Kb = [OH⁻] [HX] / [X⁻]

To convert Ka to Kb we must use water equilibrium:

2H₂O ⇄ H₃O⁺ + OH⁻

Where Kw = 1x10⁻¹⁴ = [OH⁻] [H₃O⁺]

Thus, we can obtain:

Kw = Ka*Kb

Solving for Kb:

Kw / Ka = Kb

1x10⁻¹⁴ /  2.76x10⁻⁸ =

3.62x10⁻⁷ = Kb

4 0
3 years ago
Which statement describes climate and not weather?
sasho [114]
I would answer B!! But your guess is as good as mine!!
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2 years ago
Read 2 more answers
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