Let x be the number of pens in a box.
Jill : three full boxes of pen and 2 loose pens. 3x + 2
Ben: two full boxes of pen and 14 loose pens. 2x + 14
Jill and Ben have the same pens.
Jill = Ben
3x+2 = 2x + 14
3x - 2x = 14 - 2
1x = 12
x = 12
To check:
Jill = Ben
3x + 2 = 2(x) + 14
3(12) + 2 = 2(12) + 14
36 + 2 = 24 + 14
38 = 38
There are 12 pens or a dozen of pens in a full box.
Answer:
Solution: x = -2; y = 3 or (-2, 3)
Step-by-step explanation:
<u>Equation 1:</u> y = -5x - 7
<u>Equation 2:</u> -4x - 3y = -1
Substitute the value of y in Equation 1 into the Equation 2:
-4x - 3(-5x - 7) = -1
-4x +15x + 21 = -1
Combine like terms:
11x + 21 = - 1
Subtract 21 from both sides:
11x + 21 - 21 = - 1 - 21
11x = -22
Divide both sides by 11 to solve for x:
11x/11 = -22/11
x = -2
Now that we have the value for x, substitute x = 2 into Equation 2 to solve for y:
-4x - 3y = -1
-4(-2) - 3y = -1
8 - 3y = -1
Subtract 8 from both sides:
8 - 8 - 3y = -1 - 8
-3y = -9
Divide both sides by -3 to solve for y:
-3y/-3 = -9/-3
y = 3
Therefore, the solution to the given systems of linear equations is:
x = -2; y = 3 or (-2, 3)
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3/12 + 10/12 = 13/12 because the points lie in-between the 1/6 and 2/6 marks and the 6/6 and 7/6 marks.
Answer:
3x^2 +3xh +h^2 -10 x- sh + 1, H=0
Step-by-step explanation: