Answer:
No, it is not
Step-by-step explanation:
Here, we want to check if what we have is a function
For a relation to be a function, the mapping must be one to one or many to one
This mean, for every x there must be one y or for every y, there must can be multiple x
But never is it that there are many y for a single x
Looking at the value 0
on the domain, we can see -2 and 1 as the values
Thus, this is not a function
