Answer:
The quantity of water in the tank after 15 days is 1610.0 gallons OR 1.61 × 10³ gallons.
Step-by-step explanation:
The amount of water in the tank after 15 days is given by the series
910+(−710)+810+(−610)+⋯+310+(−110)+210
From the series, we can observe that, if water is added for a particular day then water will be drained the following day.
Also, for a day when water is to be added, the quantity to be added will be 100 gallon lesser than the quantity that was last added. Likewise, for a day when water is to be drained, the quantity to be drained will be 100 gallons lesser than the quantity that was last drained.
Hence, we can complete the series thus:
910+(−710)+810+(−610)+710(-510)+610(-410)+510(-310)+410(-210)+310+(−110)+210
To evaluate this, we get
910-710+810-610+710-510+610-410+510-310+410-210+310-110+210
= 1610.0 gallons
Hence, the quantity of water in the tank after 15 days is 1610 gallons OR 1.61 × 10³ gallons.
Answer:
In what article are you most likely to find the sentence “The coma streamed out until it formed a tail of dust and light”?
“Comets in the Sky”
“How to Punctuate Sentences”
“Water Under the Bridge”
“Medical Histories”
Step-by-step explanation:
B. 11
Although eleven is a prime number, it's two factors (1 and 11) are odd integers
Answer:
x = 5
Step-by-step explanation:
3 = x/ 3 + 4
This is same as
3/1 = x/ 3 + 4
Then cross multiply
1(x + 4) = 3× 3
x + 4 = 9
x = 9 - 4
x = 5
Answer:
5/12 barrel/hour
Step-by-step explanation:
Type this as a fraction:
(1/6) barrel
--------------------
(2/5) hours
Division by 2/5 is equivalent to multiplication by 5/2:
1 5
--- barrel * -------------- = 5/12 barrel/hour
6 2 hours
Alternatively, this problem could be done using decimal fractions:
0.1667 barrel
-------------------- = 0.416666 barrel/hour = 5/12 barrel/hour
0.4 hours
