Answer:
The initial speed of the car was 80 ft/s.
Step-by-step explanation:
The deceleration is the rate at which the car speed decreases. In this case the speed of the car goes all the way down to 0 ft/s and in order to do that it travelled 50 ft. So we will call the initial speed at which the car started to brake "v_0" and use Torricelli's equation to find it. The equation is given by:
v^2 = (v_0)^2 + 2*a*S
Where v is the final speed, v_0 is the initial speed, a is the rate of acceleration and S is the space travelled. Using the values that the problem gave to us we have:
0^2 = (v_0)^2 - 2*64*50
0 = (v_0)^2 - 6400
(v_0)^2 = 6400
v_0 = sqrt(6400) = 80 ft/s
Notice that in this case "a" was negative, since the car was decelerating instead of accelerating.
The initial speed of the car was 80 ft/s.
The table of possible values when graphing
X Y
-2 9
-1 5
0 1
1 -3
2 -7
The intercepts x (1/4,0) and y (0,1)
I think that -25 should be +25.
so it would be (7x-5)^2
0 = 2 - 3y + 12x
0 = 12x - 3y + 2
3y = 12x + 2
3 3
y = 4x + ²/₃
Change the problem into an equation in slope-intercept form.
