We know that the Pythagorean theorem applies only to right triangles, therefore the original vectors must be parallel to the legs of a right triangle.
In other words, they must be orthogonal (i.e. perpendicular to each other) in order that the Pythagorean theorem applies.
24- series
25- parallel
26- no, because they’re connected in series
27- yes, because they’re connected in parallel
conducted
Conduction occurs when a substance is heated, particles will gain more energy, and vibrate more. These molecules then bump into nearby particles and transfer some of their energy to them. This then continues and passes the energy from the hot end down to the colder end of the substance.
We are asked in this problem to determine the power wasted given the two voltages: 50,000 and 12,000 volts. By physics, the formula to determine power using volts is expressed as P = VI where P is in watts, V is in volts and I, current, is in Amperes. In this case, we just have to plug the given data to the equation named.
1) P1 = 50,000*I
2) P2 = 12,000 * I
P1 - P2 = (50,000-12,000)*I
ΔP = 48,000 I
So the power wasted then is equal to 48,000 times the current employed to achieve power. I should be specified as well to determine the exact difference.
Explanation:
y = y₀ + v₀ t + ½ at²
For the first ball:
0 = h + v₀ t − 4.9t²
For the second ball:
0 = h − 4.9 (t−1)²
a) If h = 20.0, find v₀.
0 = 20 − 4.9 (t−1)²
t = 3.02 s
0 = 20 + v₀ (3.02) − 4.9 (3.02)²
v₀ = 8.18 m/s
Graph:
desmos.com/calculator/uk1wzkxybt
If v₀ is given, find h.
First, find t in terms of v₀:
h + v₀ t − 4.9t² = h − 4.9 (t−1)²
v₀ t − 4.9t² = -4.9 (t−1)²
v₀ t − 4.9t² = -4.9 (t² − 2t + 1)
v₀ t − 4.9t² = -4.9t² + 9.8t − 4.9
v₀ t = 9.8t − 4.9
(9.8 − v₀) t = 4.9
t = 4.9 / (9.8 − v₀)
Therefore:
h = 4.9 (4.9 / (9.8 − v₀) − 1)²
bi) If v₀ = 6.0 m/s:
h = 4.9 (1 / (9.8 − 6.0) − 1)²
h = 2.66 m
bii) If v₀ = 9.5 m/s:
h = 4.9 (1 / (9.8 − 9.5) − 1)²
h = 26.7 m
c) As found in part a, the time it takes for the first ball to land is:
t = 4.9 / (9.8 − v₀)
If v₀ is greater than 9.8 m/s, the time becomes negative, which isn't possible. Therefore, vmax = 9.8 m/s. At this speed, the ball would reach its highest point after 1 second, the same time that the second ball is dropped. Two balls dropped at the same time from different heights cannot land at the same time.
d) If v₀ is less than 4.9 m/s, the time for the first ball to land becomes less than 1 second. Which means it will have already landed before the second ball is dropped. Therefore, vmin = 4.9 m/s.
