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Alexeev081 [22]
3 years ago
15

a boat travels 40 miles in two hours, speeds up to travel the next 80 miles in three hours then slows down to travel the last 40

miles in three hours. What is the average speed of the boat the entire trip?
Physics
2 answers:
Bumek [7]3 years ago
6 0

Answer:

Average speed, v = 2 miles/hour

Explanation:

It is given that, a boat travels 40 miles in two hours, speeds up to travel the next 80 miles in three hours then slows down to travel the last 40 miles in three hours.

Total distance travelled, d = 40 + 80 + 40 = 160 miles

Total time taken by the boat, t = 2 + 3 + 3 = 8 hours

We need to find the average speed of the boat the entire trip. It is given by total distance travelled by the boat divided by total time taken. Mathematically,

v=\dfrac{d}{t}

v=\dfrac{160\ miles}{8\ hours}

v = 2 miles/hour

So, the average speed of the boat the entire trip is 2 miles/hour. Hence, this is the required solution.

Over [174]3 years ago
5 0

Answer:

The average speed of the boat the entire trip is 20 miles/hour.

Explanation:

Given that,

A boat travels 40 miles in 2 hours next 80 miles in three hours and last 40 miles in three hours.

We need to calculate the average speed of the boat the entire trip

Using formula of average speed

v_{avg}=\dfrac{D}{T}

Where, D = total distance

T = total time

Put the value into the formula

v_{avg}=\dfrac{40+80+40}{2+3+3}

v_{avg}=\dfrac{160}{8}

v_{avg}=20\ miles/hour

Hence, The average speed of the boat the entire trip is 20 miles/hour.

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The part B of the question is missing and it is;

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Explanation:

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Plugging in the relevant values into the initial velocity equation gives;

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(y1 - y0) = ut + ½at²

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A box of mass 20kg is pulled up an inclined plane by a force of 285N. Given that the value of the incline angle is 30 degrees an
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Given :

Mass of box , m = 250 kg.

Force applied , F = 285 N.

The value of the incline angle is 30°.

the coefficient of dynamic friction is \mu=0.72 .

To Find :

The speed with which the box is moving with, assuming it takes 4 seconds to reach the top of the incline.

Solution :

Net force applied in box is :

F=285 - mgsin\ \theta - \mu mg cos \ \theta\\ \\F=285-mg( sin \ \theta - \mu cos\ \theta)\\\\F=285 - 20\times 10( \dfrac{1}{2}+0.72\times \dfrac{\sqrt{3}}{2})\\\\F=60.29\ N

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Therefore, the speed of box is 12.04 m/s.

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