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umka2103 [35]
3 years ago
10

A trumpeter is placed on a moving sidewalk that moves at a constant velocity of 4.5 m/s. A listener is standing 6.0 m in front o

f the trumpeter on the same sidewalk. The trumpeter plays a note of frequency 290 Hz. The air is still and the speed of sound is What frequency of the note does the listener hear?
Physics
1 answer:
bearhunter [10]3 years ago
5 0
You didn't actually include the speed of sound. But it doesn't matter for this question. If the trumpeter and the listener are on the same moving sidewalk then the distance between them is not changing. The Doppler shift only happens when the distance between the source and the Observer is changing. So the Listener hears the same 290 Hertz that the trumpeter is generating.
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What is an emergent ray​
dangina [55]

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Explanation:

the light ray leaving a medium in contrast to the entering or incident ray.

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2 years ago
How many electrons flow through a point in a wire in 7.00 s if there is a constant current of I = 4.35 A?
OLEGan [10]

Answer:

1.90×10²⁰ Electrons

Explanation:

From the question,

Q = It.................... Equation 1

Where Q = charge flowing through the wire, I = current, t = time

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Q = 4.35(7.00)

Q = 30.45 C.

But,

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therefore,

30.45 C = 30.45/1.6×10⁻¹⁹  electrons

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A 10 kg block is attached to a light cord that is wrapped around the pulley of an electric motor, as shown above. At what rate i
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3 years ago
Which of the following statements apply to electric charges? please help this is the only question i need done!!
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8 0
3 years ago
Read 2 more answers
What is the strength of the electric field 3.0 cm from a small glass bead that has been charged to + 8.0 nc ?
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Thinking the small glass bead as a single point charge, the electric field generated by it is given by
E(r) = k_e  \frac{Q}{r^2}
where
k_e = 8.99 \cdot 10^9 N m^2 C^{-2} is the Coulomb's constant
Q=8.0 nC=8.0 \cdot 10^{-9} C is the charge of the bead
r=3.0 cm=0.03 m is the distance at which we calculate the field.

Using these data, we find:
E=(8.99 \cdot 10^9 N m^2 C^{-2} ) \frac{(8.0 \cdot 10^{-9} C}{0.03 m)^2}=8.0 \cdot 10^4 N/C
6 0
3 years ago
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