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3 years ago

Help me fast 50 points!!!!!!!!

Mathematics

2 answers:

mihalych1998 [28]3 years ago

7 0

Answer:

Step-by-step explanation:

There are 14 data points on the plot

The median is the middle value, which is between the 7th and 8th data points

Since it is even, we find the average of the 7th and 8th data points

Add the 7th and 8Th data points values and divide by 2

( 30+30)/2 = 60/2 = 30

The median is 30

Gala2k [10]3 years ago

5 0

Answer:

Step-by-step explanation:

Middle numbers are 30 and 30 so you add them and then divide by two:

$\frac{30 + 30}{2}$ = $\frac{60}{2}$ <em>= </em>30

You might be interested in

Work out the size angles x,y and z

Andreas93 [3]

Answer:

x = y = 14

z = 70

Step-by-step explanation:

As we can see from the markings, x = y

So we have an isosceles triangle in ABD

the sum of angles in a triangle is 180

52 + x + y = 180

x + y = 180-52

x + y = 28

so since x = y

x = y = 14

To get z, we have that;

52 + z + 14 + 44 = 180

z + 110 = 180

z = 180-110

z = 70

3 0

2 years ago

For each vector field f⃗ (x,y,z), compute the curl of f⃗ and, if possible, find a function f(x,y,z) so that f⃗ =∇f. if no such f

butalik [34]

$\vec f(x,y,z)=(2yze^{2xyz}+4z^2\cos(xz^2))\,\vec\imath+2xze^{2xyz}\,\vec\jmath+(2xye^{2xyz}+8xz\cos(xz^2))\,\vec k$

Let

$\vec f=f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k$

The curl is

$\nabla\cdot\vec f=(\partial_x\,\vec\imath+\partial_y\,\vec\jmath+\partial_z\,\vec k)\times(f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k)$

where $\partial_\xi$ denotes the partial derivative operator with respect to $\xi$ . Recall that

$\vec\imath\times\vec\jmath=\vec k$

$\vec\jmath\times\vec k=\vec i$

$\vec k\times\vec\imath=\vec\jmath$

and that for any two vectors $\vec a$ and $\vec b$ , $\vec a\times\vec b=-\vec b\times\vec a$ , and $\vec a\times\vec a=\vec0$ .

The cross product reduces to

$\nabla\times\vec f=(\partial_yf_3-\partial_zf_2)\,\vec\imath+(\partial_xf_3-\partial_zf_1)\,\vec\jmath+(\partial_xf_2-\partial_yf_1)\,\vec k$

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

$\nabla\times\vec f=\vec0$

which means $\vec f$ is indeed conservative and we can find $f$ .

Integrate both sides of

$\dfrac{\partial f}{\partial y}=2xze^{2xyz}$

with respect to $y$ and

$\implies f(x,y,z)=e^{2xyz}+g(x,z)$

Differentiate both sides with respect to $x$ and

$\dfrac{\partial f}{\partial x}=\dfrac{\partial(e^{2xyz})}{\partial x}+\dfrac{\partial g}{\partial x}$

$2yze^{2xyz}+4z^2\cos(xz^2)=2yze^{2xyz}+\dfrac{\partial g}{\partial x}$

$4z^2\cos(xz^2)=\dfrac{\partial g}{\partial x}$

$\implies g(x,z)=4\sin(xz^2)+h(z)$

Now

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+h(z)$

and differentiating with respect to $z$ gives

$\dfrac{\partial f}{\partial z}=\dfrac{\partial(e^{2xyz}+4\sin(xz^2))}{\partial z}+\dfrac{\mathrm dh}{\mathrm dz}$

$2xye^{2xyz}+8xz\cos(xz^2)=2xye^{2xyz}+8xz\cos(xz^2)+\dfrac{\mathrm dh}{\mathrm dz}$

$\dfrac{\mathrm dh}{\mathrm dz}=0$

$\implies h(z)=C$

for some constant $C$ . So

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+C$

3 0

3 years ago

Solve for x: 2-3(2x-1)=-6x+5

horrorfan [7]

Answer:

x=-1

Step-by-step explanation:

1.) 2-3(2x-1)=-6x+5

2.) -1(-2x-1)=-6+5

3.) (2x+1)=-6+5

4.) (2x+1)=-1

5.) 2x=-2

6.) x=-1

3 0

3 years ago

a 3 point shooting contest player attempts 25 shots and makes 17 of them, find the ratio of the shots missed________

UNO [17]

So 25 attempted
17 made
so missed=attempted-made=25-17=8
there are different ratios
there is
attempted:missed=25:8
made:missed=17:8
attemped:made=25:17

6 0

3 years ago

If 6 is subtracted from 3 times a certain number, the result is 84. Find the number.

Soloha48 [4]

Answer:

Step-by-step explanation:

So to do this you would set up the equation $3x-6=84$ than you would add 6 to both sides so you would get $3x=90$ than you would divide 3 from both sides so $x=30$ and that is the final answer which is correct

7 0

3 years ago

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