To solve these problems, you usually have a favor the numerator. For example, on #7, label your terms, 1 from m^2 is A, -6m from -6 is B and your constant, 8, is C. Next you have to find out what two numbers can be multiplied to give you for C term but can also add together to give you your B term. For this specific problem, -4 and -2 gives you 8 and also adds to be -6. After that, you put your -4 and -2 into their own separate parentheses along with the M from M^2. It should look this like: (m-4)(m-2)/(m-2). Now you notice that the binomial on the bottom and one of the binomials on top is the exact same, so you would cancel that out and your answer would be (m-4).
