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Aneli [31]
3 years ago
15

2n > -20 Please help N=?

Mathematics
2 answers:
serg [7]3 years ago
6 0
I just need points but I hope you do good
Wewaii [24]3 years ago
3 0

Answer:

The value of x>-10

Step-by-step explanation:

The interval notation if you need it is (-10,♾)

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Answer? with solution please. Will automatically report kung wala:)
serious [3.7K]

Answer:

B

Step-by-step explanation:

Communitive only works with multiplication and addition. It states that if you have something adding or subtracting something switched around, they are the same. B has that so the answer is B

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4 0
3 years ago
Classify the absolute value statements based on their values. |3| |-3| |-4| |4| |-5| |5|
Fittoniya [83]
The answers would be 3, 3, 4, 4, 5, 5. those are the answers. I don't know if that is what you wanted me to answer or not.
5 0
3 years ago
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How many soultions does 5(x-3)+6=5x-9
olya-2409 [2.1K]

5(x - 3) + 6 = 5x - 9 has no solution

<em><u>Solution:</u></em>

We have to find the number of solutions for the given equation

Given equation is:

5(x - 3) + 6 = 5x - 9

Multiply the terms inside with bracket with constant outside the bracket

5x - 15 + 6 = 5x - 9

Add the constants in left hand side of equation

5x - 9 = 5x - 9

If the coefficients are the same on both sides, then the sides will not equal, therefore no solutions will occur.

Here, 5x - 9 = 5x - 9

The coefficients are same in both sides of equation

Therefore, the equation has no solution

5 0
3 years ago
Toni can carry up to 18 lb in her backpack. Her lunch weighs 1 lb, her gym clothes weigh 2 lb, and her books (b) weigh 3 lb each
MrRissso [65]
<span>Toni can carry five books in her backpack. You must start by subtracting the weight of the other required items. Toni's lunch which is one pound and gym clothes which are two pounds. This can be calculated by 18-1-2=15. Toni has 15 pounds left to carry books. She should divide this by the weight of each book, which is three pounds. 15/3=5. Therefore, Toni can carry five books.</span>
3 0
3 years ago
Polygon F has an area of 36 square units. Aimar drew a scaled version of Polygon F and labeled it Polygon G. Polygon G has an ar
Free_Kalibri [48]

Answer:

1/3

Step-by-step explanation:

The area of Polygon GGG is \dfrac19  

9

1

​  start fraction, 1, divided by, 9, end fraction the area of Polygon FFF.

Each side of Polygon FFF was multiplied by a certain value, known as the scale factor , to result in an area that is \dfrac19  

9

1

​  start fraction, 1, divided by, 9, end fraction the area of Polygon FFF.

[Show me an example of how scale factor affects area]

\dfrac1{10}  

start fraction, 1, divided by, 10, end fraction

 

 

\begin{aligned} A &= \left(l\times\dfrac1{10}\right)\times\left(w\times\dfrac1{10}\right) \\ \\ A&= l\times w\times\dfrac1{10}\times\dfrac1{10} \\ \\ A&= lw \times \left(\dfrac1{10}\right)^2\end{aligned}  

 

 

 

 

 

 

 

 

\dfrac1{10}  

start fraction, 1, divided by, 10, end fraction\left(\dfrac1{10}\right)^2  

 

left parenthesis, start fraction, 1, divided by, 10, end fraction, right parenthesis, start superscript, 2, end superscript

Hint #22 / 3

The area of a polygon created with a scale factor of \dfrac1x  

x

1

​  start fraction, 1, divided by, x, end fraction has \left(\dfrac1{x}\right)^2(  

x

1

​  )  

2

left parenthesis, start fraction, 1, divided by, x, end fraction, right parenthesis, start superscript, 2, end superscript the area of the original polygon:

\left(\text{scale factor}\right)^2=\text{fraction of the area the scale copy has}(scale factor)  

2

=fraction of the area the scale copy hasleft parenthesis, s, c, a, l, e, space, f, a, c, t, o, r, right parenthesis, start superscript, 2, end superscript, equals, f, r, a, c, t, i, o, n, space, o, f, space, t, h, e, space, a, r, e, a, space, t, h, e, space, s, c, a, l, e, space, c, o, p, y, space, h, a, s

The area of Polygon GGG is \dfrac19  

9

1

​  start fraction, 1, divided by, 9, end fraction the area of Polygon FFF. Let's substitute \dfrac19  

9

1

​  start fraction, 1, divided by, 9, end fraction into the equation to find the scale factor.

\left(\dfrac1{?}\right)^2=\dfrac19(  

?

1

​  )  

2

=  

9

1

​  left parenthesis, start fraction, 1, divided by, question mark, end fraction, right parenthesis, start superscript, 2, end superscript, equals, start fraction, 1, divided by, 9, end fraction

The scale factor is \dfrac13  

3

1

​  start fraction, 1, divided by, 3, end fraction.

Hint #33 / 3

Aimar used a scale factor of \dfrac13  

3

1

​  start fraction, 1, divided by, 3, end fraction to go from Polygon FFF to Polygon GGG.

4 0
3 years ago
Read 2 more answers
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