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Viktor [21]
3 years ago
5

19 points if you answer this question

Mathematics
2 answers:
Alborosie3 years ago
7 0
Option d is correct for the question
mihalych1998 [28]3 years ago
7 0
It is b I think because of the question is
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Help pleaseeee???!!!
jolli1 [7]

Answer:

h=8

Step-by-step explanation:\frac{-7}{8} h= -7\\\\(\frac{8}{-7} )(\frac{-7}{8} h)= -7 (\frac{8}{-7} )\\\\\frac{-56}{-56}h = \frac{56}{7}\\\\ h=\frac{56}{7}\\\\h=8

the goal is to isolate the variable, get it all by itself. to do that in this problem, we have to move the -7/8 away from the h. we do this by multiplying by the reciprocal (the opposite of the fraction). The reciprocal of -7/8 is 8/-7. So multiply both sides by this and you will get h=8

8 0
3 years ago
The graph shows the height of a plant over a 2-month growth period. Calculate the rate of change per day.​
Mkey [24]

Answer:

14/61 cm per day

Step-by-step explanation:

Use the slope formula  \frac{y_{2}  - y_{1}}{x_{2}  - x_{1}}

Plug it in \frac{16-2}{61-0}

Simplify \frac{14}{61}

3 0
3 years ago
Factor Completely'''​
vekshin1

Answer:

4x^2(x-2)(x+6)

Step-by-step explanation:

Factor 4x^2

4x^2(x^2)+4x^2(4x)-4x^2(-12)

4x^2(x^2+4x-12)

4x^2(x-2)(x+6)

<em>good luck, hope this helps :)</em>

5 0
3 years ago
Simplify(3 square root 3 x square root 5 square root of 3)Square root of negative two
Assoli18 [71]

Answer:

9√10 (nine square root ten)

Step-by-step explanation:

(3√3  .√5.√3.)√2

= (3√3*3.√5)√2

=(3*3.√5)√2

=(9√5) √2

=9√5*2

=9√10

8 0
3 years ago
The heights of young women follow a Normal distribution with a mean u = 64.5 inches and standard deviation o = 2.5 inches. The p
mash [69]

Answer:

The heights of young women follow a Normal distribution with a mean u = 64.5 inches and standard deviation o = 2.5 inches. The probability that the mean height of an SRS of 10 young women exceeds 66.5 inches is _

normalcdf(66.5, 99999999, 64.5, 2.5)

1 - normalcdf(66.5, 99999999, 64.5, 0.7906)

normalcdf(-99999999, 66.5, 64.5, 2.5)

normalcdf(66.5, 99999999, 64.5, 0.7906)

normalcdf(66.5, 99999999, 0, 1)

1 - normalcdf(66.5, 99999999, 64.5, 2.5)

1 - normalcdf(66.5, 99999999, 0, 1)

normalcdf(--99999999, 66.5, 64.5, 0.7906)

plz need help number 1 2 3 4 5 are pic

8 0
3 years ago
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