A. 1/5 fish
We know that 2/5 of Mike's fish are clownfish. Therefore, 3/5 are not clownish as 5/5 – 2/5 = 3/5. Also, if you look at the model, there are five pieces. If we assume that model represents the whole of Mike's fish and you take away two pieces, you are left with 3/5. So we know that the remaining fish is 3/5
Next, we know that of these 3/5 fish, 1/3 is damselfish, so we need to find 1/3 of 3/5. To do this, we must multiply 1/3 by 3/5 as "of" means multiply in Math.
So: 1/3 • 3/5 = 1 • 3/3 • 5 = 3/15 3 ÷ 3 = 1 and 15 ÷ 3 = 5 3/15 = 1/5
1/5 of Mike's fish are damsel fish
B. 2/5 fish
Now we know that 1/5 of Mike's fish is damselfish, and 2/5 is clownfish. To find the fraction of his fish that are neither, therefore, we must subtract their sum from the whole.
First, we add 1/5 and 2/5 together. Adding the numerators, 1 and 2, we get 1/5 + 2/5 = 3/5
Next, we subtract: 5/5 – 3/5 = 2/5, so 2/5 of his fish are neither clownfish or damselfish
And if you look at the model again, you can see that if you cross out 1 piece for the damselfish, and 2 pieces for the clownfish, you are left with 2/5
The answer would be $26.45.
What you do is on a calculator: 115 x 23%
Hope this helps :)
Answer:
17.6 m²
Step-by-step explanation:
Given the ratio of similar shapes = a : b, then
area of shapes = a ² : b²
Δ PTQ and Δ PRS are similar and so the ratio of corresponding sides are equal, that is
PT : PR = 6 : 9 = 2 : 3, thus
ratio of areas = 2² : 3² = 4 : 9
let the area of Δ PQT be x, then using proportion
= ( cross- multiply )
9x = 4(x + 22) ← distribute
9x = 4x + 88 ( subtract 4x from both sides )
5x = 88 ( divide both sides by 5 )
x = 17.6
Thus area of Δ PQT = 17.6 m²
X = - 3 is a parallele to y-axis at x= - 3