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3 years ago

A spherical water tank has a diameter of 14.5 feet.

Mathematics

1 answer:

lawyer [7]3 years ago

7 0

Answer:

1595.45 ft3

Step-by-step explanation:

The formula is (4/3) *3.14*r^3

since the diameter is 14.5, the radius is 7.25

(4/3) *3.14*(7.25^3)

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Does this graph show a function? Explain how you know.

beks73 [17]

Answer:

No, the graph fails the vertical line test

Step-by-step explanation:

To determine if the graph is a function, we can use the vertical line test.

Use a vertical line, if the vertical passes through two or more points, the graph is not a function

Looking at the y axis ( which is a vertical line), it passes through two points

This means the graph is not a function

No, the graph fails the vertical line test

5 0

1 year ago

Simplify this expression.

GalinKa [24]

I believe the answer is C

6 0

3 years ago

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What is the area of the hexagon below? 6CM

Brums [2.3K]

365717262cm2
I think they will be able with the one that

4 0

3 years ago

PLS TRY TO ANSWER ASAP.

Harrizon [31]

Answer:

0.075 m/min

Explanation:

You need to use derivatives which is an advanced concept used in calculus.

1. Write the equation for the volume of the cone:

$V=\dfrac{1}{3}\pi r^2h$

2. Find the relation between the radius and the height:

r = diameter/2 = 5m/2 = 2.5m

h = 5.2m

h/r =5.2 / 2.5 = 2.08

3. Filling the tank:

Call y the height of water and x the horizontal distance from the axis of symmetry of the cone to the wall for the surface of water, when the cone is being filled.

The ratio x/y is the same r/h

x/y=r/h

y = x . h / r

The volume of water inside the cone is:

$V=\dfrac{1}{3}\pi x^2y$

$V=\dfrac{1}{3}\pi x^2(2.08)\cdot x\\\\\\V=\dfrac{2.08}{3}\pi x^3$

4. Find the derivative of the volume of water with respect to time:

$\dfrac{dV}{dt}=2.08\pi x^2\dfrac{dx}{dt}$

5. Find x² when the volume of water is 8π m³:

$V=\dfrac{2.08}{3}\pi x^3\\\\\\8\pi=\dfrac{2.08}{3}\pi x^3\\\\\\ 11.53846=x^3\\ \\ \\ x=2.25969\\ \\ \\ x^2=5.1062$ m²

6. Solve for dx/dt:

$1.2m^3/min=2.08\pi(5.1062m^2)\dfrac{dx}{dt}$

$\dfrac{dx}{dt}=0.03596m/min$

7. Find dh/dt:

From y/x = h/r = 2.08:

$y=2.08x\\\\\\\dfrac{dy}{dx}=2.08\dfrac{dx}{dt}\\\\\\\dfrac{dy}{dt}=2.08(0.035964m/min)=0.0748m/min\approx0.075m/min$

That is the rate at which the water level is rising when there is 8π m³ of water.

4 0

3 years ago

Make sure to focus on the arms and feet of the man. It’s my final Set for 100 points !

Paha777 [63]

Shoes= 10

Man= 5

Tie= 4

So, 10+5*4= 30 <— Answer

How to get variables:

Shoes:

3 shoes are equal to 30, so to find the value of the shoes use 3x=30. X=10

Man:

2 men and a shoe is equal to 20. So, 2x+10=20

2x=10

X=5

Tie:

2 ties and a man are 13. So,

2x+5=13

2x=8

X=4

3 0

3 years ago

Read 2 more answers