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bonufazy [111]
2 years ago
8

Is 3/6 and 1/2 equivalent

Mathematics
2 answers:
lilavasa [31]2 years ago
7 0

Answer:

yes

Step-by-step explanation:

since you can simplify 3/6, when dividing the numerator and denominator by 3

plz brainliest :)

erica [24]2 years ago
6 0

Answer:

Step-by-step explanation:

Yes

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Solve for c<br><br><br> R=5(c/a-0.3)
aalyn [17]

we have

R=5(c/a-0.3)

Solve for c--------> that means that clear variable c

so

Divide by 5 both sides

R/5=(c/a-0.3)

Adds 0.3 both sides

(R/5)+0.3=(c/a)

Multiply by a both sides

a[(R/5)+0.3]=c

so

c=a[(R/5)+0.3]

therefore

<u>the answer is</u>

c=a[(R/5)+0.3]

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3 years ago
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Which angle relationship alone could be used as a reason that two angles are congruent?
zimovet [89]

Supplementary angles

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=77%20%5Ctimes%20100" id="TexFormula1" title="77 \times 100" alt="77 \times 100" align="absmidd
Inessa [10]
77 times 100 is 7,700. So your answer is 7,700
5 0
3 years ago
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Solve equation: 4*4^x-6^x=18*3^2x​
Tamiku [17]

Answer: x-2/x(x-1)

Step-by-step explanation:

What grade are you in this is college stuff.

6 0
2 years ago
Can anyone help? There’s 2 solutions. (50 points + brainliest)
Andreyy89
Domain:

x-1\neq0\\\\\boxed{x\neq1}

As we see in a numerator we have a square, so (3x+1)^2 is always 0 or more. Now, there are two possibilities:

1. (3x+1)^2>0

We divide two numbers, and first one is positive, so the result will be also positive (it canot be 0 in this case) when x-1\ \textgreater \ 0. So:

 x-1\ \textgreater \ 0\\\\\boxed{x\ \textgreater \ 1}

2. (3x+1)^2=0

In this case the result wil be 0 (we have ≥ 0 in our inequality, so it will be a solution).

(3x+1)^2=0\\\\3x+1=0\\\\3x=-1\qquad|:3\\\\\\\boxed{x=-\dfrac{1}{3}}

So the solution to this inequality is:

\boxed{x=-\dfrac{1}{3} \qquad\vee\qquad x\ \textgreater \ 1}
7 0
3 years ago
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