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Luba_88 [7]
2 years ago
14

What is the sum of the exterior angles in a regular 15 gon

Mathematics
1 answer:
bezimeni [28]2 years ago
6 0

9514 1404 393

Answer:

  360°

Step-by-step explanation:

The sum of exterior angles of any convex polygon is 360°.

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3 / m + 4 - 4 / m = 6 (i) Show that this equation can be written as 6m^2 + 25m+16= 0
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Answer:

Proved Below

Step-by-step explanation:

\sf \frac{3}{m+4} - \frac{4}{m} = 6\\LCM = m(m+4)\\Multiplying \ both \ sides \ by\ m(m+4)\\3m - 4(m+4) = 6m(m+4)\\3m-4m-16 = 6m^2+24m\\-m-16 = 6m^2+24m\\Adding\ m\ to\ both\ sides\\-16 = 6m^2+24m+m\\-16 = 6m^2+25m\\Adding \ 16 \ to \ both \ sides\\0 = 6m^2+25m+16\\OR\\6m^2+25m+16 = 0

Hence, Proved that \sf \frac{3}{m+4} - \frac{4}{m} = 6 is equivalent to \sf 6m^2+25m+16 = 0.

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3 years ago
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-5y+8x=-18<br><br> 5y+2x=58<br><br> Solve for x and y
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in -5y+8x=-18 and 5y+2x=58

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QUICK HELP!!!!!!!!!!!!
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