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3 years ago

Help me please......

Mathematics

1 answer:

statuscvo [17]3 years ago

5 0

Answer:

So x changes by 10 and the you do 25-6.25

then y/x =1.875x

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Rule set for 18250 , 18500 , 19000 , 20000

Rus_ich [418]

I thought doubling everytime except for the number 19000 because if you do 250 × 2 = 500 so then you do 500×2=1000.

3 0

3 years ago

The Barkers started their trip with a full tank of gas and a total of 39,872 miles on their car. They stopped 4 hours later and

lara [203]

Answer:

27.5 miles per gallon

Step-by-step explanation:

3 0

2 years ago

Mario says that the expression 4+3n² has four terms: 4, 3, n, and 2. Is he correct? explain.

stich3 [128]

Mario says that the expression $4+3n^2$ has four terms: 4, 3, n, and 2. Mario is incorrect

<em><u>Solution:</u></em>

Given that the expression is:

$4+3n^2$

Given that, Mario says that the above expression has four terms

But Mraio is incorrect

Because the given expression has two terms only

4 is one of the term

$3n^2$ is another term

So there are totally 2 terms only

A term can be a signed number, a variable, or a constant multiplied by a variable or variables

Here 3 is a constant multiplied by $n^2$

So, $3n^2$ is one term

Each term in an algebraic expression is separated by a + sign or - sign

Thus there are two terms in mario expression

8 0

3 years ago

Write and expression for “the sum of d and 9”

Natali [406]

Sum means to Add.

So the sum of d and 9 would be d + 9

5 0

3 years ago

Read 2 more answers

A human resources representative claims that the proportion of employees earning more than $50,000 is less than 40%. To test thi

bearhunter [10]

Answer:

The statistic for this case would be:

$z=\frac{\hat p -p_o}{\sqrt{\frac{\hat p(1-\hat p)}{n}}}$

And replacing we got:

$z= \frac{0.436-0.4}{\sqrt{\frac{0.436*(1-0.436)}{700}}}= 1.92$

Step-by-step explanation:

For this case we have the following info:

$n =700$ represent the sample size

$X= 305$ represent the number of employees that earn more than 50000

$\hat p=\frac{305}{700}= 0.436$

We want to test the following hypothesis:

Nul hyp. $p \leq 0.4$

Alternative hyp : $p>0.4$

The statistic for this case would be:

$z=\frac{\hat p -p_o}{\sqrt{\frac{\hat p(1-\hat p)}{n}}}$

And replacing we got:

$z= \frac{0.436-0.4}{\sqrt{\frac{0.436*(1-0.436)}{700}}}= 1.92$

And the p value would be given by:

$p_v = P(z>1.922)= 0.0274$

4 0

3 years ago