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lukranit [14]
3 years ago
5

One professional basketball player typically attempts eight free throws per game. Let X represent the number of free throws made

out of eight. The distribution for X is shown in the table.
Which of the following is the correct interpretation of P(X ≤ 3)?

The probability of the number of free throws made out of 8 is at most 3.
The probability of the number of free throws made out of 8 is at least 3.
The probability of the number of free throws made out of 8 is lower than 3.
The probability of the number of free throws made out of 8 is higher than 3.
Mathematics
1 answer:
tekilochka [14]3 years ago
4 0
A; the probability of the number of free throws made out of 8 is at most 3.

I might be wrong, but I’m 90% sure I’m right ☺️
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What is the volume of a crude with a side length of 3 2/3 cm
IrinaK [193]

Answer:

Volume l^3 ,where l is the side of cube

11/3^3=1331/27

=49.29cm^3

4 0
3 years ago
What is the area of this square?
Alex73 [517]
16 bc all sides of a square are congruent and area = LxW so 4x4=16
4 0
3 years ago
The value of y varies directly with x and y = 4.5 when x = 0.5. find y when x = 10
Pepsi [2]
So what you asked this is what I got

x(y) = 4.5

If x= 0.5 then 

0.5(y) = 4.5
y=9

x(y) = 4.5

10(y) = 4.5
y= 0.45



hope this helps :)





3 0
3 years ago
Andrews math teacher entered the seventh- grade students in a math competition. There was an enrollment fee of $30 and also an $
Anon25 [30]

Answer:

11

Step-by-step explanation:

You would start by subtracting $30 from $151 which is $121.

Then you would divide this by 11 which 121÷11=11

So 11 test were bought.

7 0
3 years ago
Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega
AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

To find the simplified form of the given expression :

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2 ( using the property (ab)^m=a^m.b^m )

=(2^6)(3^{-12})\times (2^{-6})(3^4) ( using the property (a^m)^n=a^{mn}

=(2^6)(2^{-6})(3^{-12})(3^4) ( combining the like powers )

=2^{6-6}3^{-12+4} ( using the property a^m.a^n=a^{m+n} )

=2^03^{-8}

=\frac{1}{3^8} ( using the property a^{-m}=\frac{1}{a^m} )

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

6 0
3 years ago
Read 2 more answers
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