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2 years ago

Please answer correctly and answer all questions I will give a heart please

Mathematics

1 answer:

NNADVOKAT [17]2 years ago

5 0

Answer:

1 = A, D 2 = B, C, D . 3 = True . 5 = D . 11 = C, D E

Step-by-step explanation:

You might be interested in

A construction company purchased some equipment costing $300,000. The value of the equipment depreciates

goldfiish [28.3K]

Answer:

$11.9\ years$

Step-by-step explanation:

we know that

The formula to calculate the depreciated value is equal to

$V=P(1-r)^{x}$

where

V is the depreciated value

P is the original value

r is the rate of depreciation in decimal

x is Number of Time Periods

in this problem we have

$P=\$300,000\\r=14\%=14/100=0.14\\V=\$50,000$

substitute the values and solve for x

$50,000=300,000(1-0.14)^{x}$

$(50,000/300,000)=(0.86)^{x}$

$(5/30)=(0.86)^{x}$

Apply log both sides

$log(5/30)=(x)log(0.86)$

$x=log(5/30)/log(0.86)$

$x=11.9\ years$

4 0

3 years ago

Read 2 more answers

Maureen went on a 3 day, 50 mile biking trip. The first day she biked 14.3 miles. The second day she biked 21.1 miles. How many

Mila [183]

Answer:

Step-by-step explanation:

14.3 + 21.1 + x = 50

35.4 + x = 50

x = 50 - 35.4

x = 14.6 <=== she biked 14.6 miles on the 3rd day

7 0

2 years ago

Read 2 more answers

The surface area of the figure

kirza4 [7]

525cm bro because i just took it right now

4 0

2 years ago

How do you solve 4(4+363562-75635)(4)/53

Mice21 [21]

Simple, use PEMDAS and then do your simple math and then your answer should be 86922.56604

4 0

2 years ago

find the component equation of the plane which is normal to the vector -2i+5j+k and which contains the point (-10;7;5).

maksim [4K]

Given:

A plane is normal to the vector = -2i+5j+k

It contains the point (-10,7,5).

To find:

The component equation of the plane.

Solution:

The equation of plane is

$a(x-x_0)+b(y-y_0)+c(z-z_0)=0$

Where, $(x_0,y_0,z_0)$ is the point on the plane and $\left< a,b,c\right>$ is normal vector.

Normal vector is -2i+5j+k and plane passes through (-10,7,5). So, the equation of the plane is

$-2(x-(-10))+5(y-7)+1(z-5)=0$

$-2(x+10)+5y-35+z-5=0$

$-2x-20+5y-35+z-5=0$

$-2x+5y+z-60=0$

$-2x+5y+z=60$

Therefore, the equation of the plane is $-2x+5y+z=60$ .

4 0

2 years ago