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The answer is
We have the following inequality.
We can divide both sides by -6, but because we divide by a negative number, we must flip the sign.
The answer is
We have the following inequality.
We can divide both sides by -6, but because we divide by a negative number, we must flip the sign.
The domain of g(x)= 3x^2 is Real number and it's range is {y∈R / y≥0}
The domain of h(x)= -3x^2 is Real number and it's range is {y∈R / y ≤0}
The domain of a function f(x) is the set of all values for which the function is defined, and the domain of a function is the set of all values that f takes on. The domain and range are defined for a relation and are the sets of all x-coordinates and all y-coordinates of ordered pairs.
The graph of f(x)= x^2 is given
We need to find the domain and range of g(x)=3x^2 and h(x)= -3x^2
The Graph of 3x^2 is different from x^2 in terms of plotting
When ,
x= -2 g(x)=12
x=-1 g(x)=3
x=0 g(x)=0
x=1 g(x)=3
x=2 g(x)=12
The Graph of -3x^2 is different from x^2 in terms of plotting
When ,
x= -2 g(x)=-12
x=-1 g(x)= -3
x=0 g(x)=0
x=1 g(x)= -3
x=2 g(x)=-12
Domain of g(x) is R and it's range is {y∈R / y≥0}
Domain of h(x) is R and it's range is {y∈R / y ≤0}
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