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iren [92.7K]
3 years ago
11

An automobile to be transported by ship is raised 7.0 m above the dock. If its gravitational potential energy is 66,000 J, what

is the automobile’s mass
Physics
1 answer:
Inessa05 [86]3 years ago
5 0

Answer:

m = 1,347\  kg

Explanation:

<u>Gravitational Potential Energy </u>

It's the energy stored in an object because of its vertical position or height in a gravitational field.

It can be calculated with the equation:

U=m.g.h

Where:

m = mass of the object

h  = height with respect to a fixed reference

g  = acceleration of gravity, usually taken as 9.8 m/s^2.

The automobile of unknown mass is raised to a height of h=7 m above the dock, assumed as a reference. The automobile has gravitational potential energy of U=66,000 J.

Let's calculate the mass by solving for m:

\displaystyle m=\frac{U}{hg}

\displaystyle m=\frac{66,000}{5*9.8}

\displaystyle m=\frac{66,000}{49}

\mathbf{m = 1,347\  kg}

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Answer:

0.557 s

Explanation:

Given:

v₀ = 5.46 m/s

v = 0 m/s

a = -9.8 m/s²

Find: t

v = at + v₀

0 m/s = (-9.8 m/s²) t + 5.46 m/s

t = 0.557 s

8 0
3 years ago
When the displacement of a mass on a spring is 12 a the half of the amplitude, what fraction of the mechanical energy is kinetic
Sveta_85 [38]
You know that when the displacement is equal to the amplitude (A), the velocity is zero, which implies that the kinetic energy (KE) is zeero, so the total mechanical energy (ME) is the potential energy (PE).

And you know that the potential energy, PE, is [ 1/2 ] k (x^2)

Then, use x = A, to calculate the PE in the point where ME = PE.

ME = PE = [1/2] k (A)^2.

At half of the amplitude, x = A/2 => PE = [ 1/2] k (A/2)^2

=> PE = [1/4] { [1/2]k(A)^2 } = .[1/4] ME

So, if PE is 1/4 of ME, KE is 3/4 of ME.

And the answer is 3/4


7 0
4 years ago
Two 1-kg objects, C and D, increase in temperature by the same amount, but the
Ede4ka [16]

The object D is made up of material Lead. The correct option is D.

<h3>What is specific heat?</h3>

The specific heat is the amount of heat required to change the temperature by 1°C. It is denoted by C.

Two 1-kg objects, C and D, increase in temperature by the same amount, but the thermal energy transfer of object C is greater than the thermal energy transfer of object D. The object C has a specific heat of 235 J/kg-K.

Q = m C ΔT

Qc > Qd

The energy transfer is proportional to specific heat.

Specific heat of D must be less. The possible material with specific heat less than the given value is for Lead material.

Thus, the correct option is D.

Learn more about specific heat,

brainly.com/question/11297584

#SPJ1

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HELP - What are some good topics to add to a Pipeline presentation? So yes, a presentation about pipelines, like for example in
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6 0
3 years ago
A proton traveling with speed 2 × 105 m/s in the -y direction passes through a region in which there is a uniform magnetic field
stepladder [879]

Answer:

\vec{E} =  1.2\times 10^5(-i)

Explanation:

Given that

Speed ,v= 2 x 10⁵ m/s ( - y direction)

B= 0.6 T (- z direction)

The resultant force on the proton given as

\vec{F}=q.\vec{E}+ q.(\vec{v}\times \vec{B})

F= m a

For uniform motion acceleration should be zero.

F = 0

0=q.\vec{E}+ q.(\vec{v}\times \vec{B})

0=\vec{E}+ (\vec{v}\times \vec{B})

0=\vec{E}+2\times 10^5(-j) \times 0.6(-k)

\vec{E} =- 2\times 10^5(-j) \times 0.6(-k)

\vec{E} =-1.2\times 10^5(i)

\vec{E} = 1.2\times 10^5(-i)

Electric filed should be apply in the negative x direction.

5 0
3 years ago
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