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3 years ago

In nature, where do fusion reactions take place?

Physics

2 answers:

pashok25 [27]3 years ago

8 0

Answer:

In nature, fusion reactions take place in the Sun and other stars.

Explanation:

that's what it says on the correct answer side

hjlf3 years ago

3 0

Fusion reactions happen in stars

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Show that any three linear operators A, B, and Ĉ satisfy the following (Ja- cobi) identity (10 pt) [[A, B] Ĉ] + [[B,C), A] + [[C

DerKrebs [107]

Answer:

Three linear operators A,B, and C will satisfy the condition $[[A, B],C] + [[B,C), A] + [[C, A], B] = 0$ .

Explanation:

According to the question we have to prove.

$[[A, B],C] + [[B,C), A] + [[C, A], B] = 0$

Now taking Left hand side of the equation and solve.

$[[A, B],C] + [[B,C), A] + [[C, A], B]$

Now use commutator property on it as,

$=[A,B] C-C[A,B]+[B,C]A-A[B,C]+[C,A]B-B[C,A]\\=(AB-BA)C-C(AB-BA)+(BC-CA)A-A(BC-CB)+(CA-AC)B-B(CA-AC)\\=ABC-BAC-CAB+CBA+BCA-CAB-ABC+ACB+CAB-ACB-BCA+BAC\\=0$

Therefore, it is proved that $[[A, B],C] + [[B,C), A] + [[C, A], B] = 0$ .

7 0

4 years ago

A veterinarian thinks that a dog has swallowed a key ring. Which types of electromagnetic waves is the doctor most likely

poizon [28]

Answer:

X rays

Explanation:

4 0

3 years ago

Read 2 more answers

A flare is launched from a life raft with an initial velocity of 192 ft/sec. How many seconds will it take for the flare to retu

DIA [1.3K]

We use the formula,

$h= ut- 16 t^2$

Here, h is the variable represents the height of the flare in feet when it returns to the sea so, h = 0 and u is the initial velocity of the flare, in feet per second and its value of 192 ft/sec.

Substituting these values in above equation, we get

$0 = 192 t - 16 t^2 \\\\ 16 t( 12 - t ) =0 \\\\ t = 12 s$ .

Here, t= 0 neglect because it is the time when the flare is launched.

Thus, flare return to the sea in 12 s.

8 0

3 years ago

A load of 800 N is lifted using a block and tackle having 5 pulleys. If the applied effort is 200 N, calculate

ser-zykov [4K]

Explanation:

Load=800N

Effort=200N

1. Mechanical Advantage = LOAD/EFFORT

= 800N/200N

= 4

2 Velocity Ratio = no. Of pulleys =5

3. Efficiency = Mechanical advantage / velocity ratio × 100%

= (4/5)×100%

=80%

4. output work= load×load distance

= 800N × 5m

= 4 × 1000J

5. Efficiency = (output work/input work) ×100%

Or, 80% = (4000J/input work) ×100%

Or, 80%/100% = 4000J/inputwork

Or, 4/5 = 4000J/inputwork

Or, input work =4000J × 5/4

Input work = 5×1000J

I hope it helped! ;-)

8 0

3 years ago

Read 2 more answers

An object is thrown vertically upward such that it has a speed of 25 m/s when it reaches two thirds of its maximum height above

AlekseyPX

Answer:

v0 = 25 m/s

vf = 0 m/s

a = -9.80 m/s^2

change in x = 31.89m

but that's only 1/3 of the hight, so i time it by 3 to get 96m

4 0

3 years ago