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3 years ago

A 1.3-kg model airplane flies in a circular path on the end of a 23-m line. The plane makes

Physics

1 answer:

storchak [24]3 years ago

4 0

(a) The plane makes 4.3 revolutions per minute, so it makes a single revolution in

(1 min) / (4.3 rev) ≈ 0.2326 min ≈ 13.95 s ≈ 14 s

(b) The plane completes 1 revolution in about 14 s, so that in this time it travels a distance equal to the circumference of the path:

(2π (23 m)) / (14 s) ≈ 10.3568 m/s ≈ 10 m/s

(c) The plane accelerates toward the center of the path with magnitude

a = (10 m/s)² / (23 m) ≈ 4.6636 m/s² ≈ 4.7 m/s²

(d) By Newton's second law, the tension in the line is

F = (1.3 kg) (4.7 m/s²) ≈ 6.0627 N ≈ 6.1 N

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If someone lost 20 pounds of fat on a diet, where did the fat go?

Nana76 [90]

Well usually when you go on a diet, you don't really want gain weight, when you lose 20 pounds on a diet to 20 pounds that you lost got used as energy for your body, if you eat healthy then you can expect to see weight loss.

7 0

3 years ago

Einstein was both a mathematician and a scientist. true or false?

Lilit [14]

Answer:

True

Explanation:

Albert Einstein was a German mathematician and physicist who developed the special and general theories of relativity. In 1921, he won the Nobel Prize for physics for his explanation of the photoelectric effect.

5 0

3 years ago

Liquid water can be separated into hydrogen gas and oxygen gas through electrolysis. 1 mole of hydrogen gas and 0.5 moles of

den301095 [7]

The temperature of the oxygen gas is 243.75 K.

Using ideal gas law to explain the answer, the absolute temperature of the gas will decrease if the number of moles of the gas increases and it will increase if the volume and/or pressure of the gas increases.

The reaction of the given elements;

$H_2 \ + \ \frac{1}{2} O_2 \ --->\ \ H_2O$

volume of the collected oxygen gas, V = 10 L

pressure of the gas, P = 1 atm

number of moles of the gas, n = 0.5

Using ideal law the temperature of the oxygen gas is calculated as follows;

$PV = nRT\\\\T = \frac{PV}{nR} \\\\where;\\R \ is \ the \ ideal \ gas \ constant = 0.08205 \ L.atm/K.mol\\\\T = \frac{1 \times 10 }{0.5 \times 0.08205} \\\\T = 243.75 \ K$

Thus, the temperature of the gas is 243.75 K.

Using ideal gas law to explain the answer. The absolute temperature of the oxygen gas is directly proportional to the product of its pressure and volume and inversely proportional to its number of moles. That is the absolute temperature of the gas will decrease if the number of moles of the gas increases and it will increase if the volume and/or pressure increases.

Learn more here: brainly.com/question/16617695

8 0

3 years ago

An object oscillates with an angular frequency of 8.0 rad/s. At t = 0, the object is at x0 = 4 cm with an initial velocity v0 =

KatRina [158]

Answer:

$\phi = 0.66 rad$

$A = 5.06 cm$

Explanation:

We have here a simple harmonic motion, so the equation of the position in this motion is:

$x(t)=Acos(\omega t+\phi)$ (1)

A: Amplitude

ω: angular frequency

φ: phase constant

If we take the derivative of x with respect to t from (1), we can find the velocity equation of this motion:

$v(t)=\frac{dx(t)}{dt}=-A\omega sin(\omega t+\phi)$ (2)

Let's evaluate (1) and (2) in t=0.

$x(0)=Acos(\phi)$ (3)

$v(0)=-A\omega sin(\phi)$ (4)

Dividing 4 by 3 we have:

$\frac{v(0)}{x(0)}=-\omega tan(\phi)$

$\phi = tan^{-1}(\frac{-v(0)}{\omega x(0)})$

$\phi = 0.66 rad$

Now, using (3) we can find the amplitude.

$A = \frac{x(0)}{cos(\phi)} = 5.06 cm$

I hope it helps!

6 0

3 years ago

Block B has mass 6.00 kg and sits at rest on a horizontal, frictionless surface. Block A has mass 2.50 kg and sits at rest on to

zzz [600]

Answer:

Explanation:

Block A sits on block B and force is applied on block A . Block A will experience two forces 1) force P and 2 ) friction force in opposite direction of motion . Block B will experience one force that is force of friction in the direction of motion .

Let force on block A be P . friction force on it will be equal to kinetic friction, that is μ mg , where μ is coefficient of friction and m is mass of block A

friction force = .4 x 2.5 x 9.8

= 9.8 N

net force on block A = P - 9.8

acceleration = ( P - 9.8 ) / 2.5

force on block B = 9.8

acceleration = force / mass

= 9.8 / 6

for common acceleration

( P - 9.8 ) / 2.5 = 9.8 / 6

( P - 9.8 ) / 2.5 = 1.63333

P = 13.88 N .

4 0

4 years ago