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artcher [175]
3 years ago
12

A 1.3-kg model airplane flies in a circular path on the end of a 23-m line. The plane makes

Physics
1 answer:
storchak [24]3 years ago
4 0

(a) The plane makes 4.3 revolutions per minute, so it makes a single revolution in

(1 min) / (4.3 rev) ≈ 0.2326 min ≈ 13.95 s ≈ 14 s

(b) The plane completes 1 revolution in about 14 s, so that in this time it travels a distance equal to the circumference of the path:

(2<em>π</em> (23 m)) / (14 s) ≈ 10.3568 m/s ≈ 10 m/s

(c) The plane accelerates toward the center of the path with magnitude

<em>a</em> = (10 m/s)² / (23 m) ≈ 4.6636 m/s² ≈ 4.7 m/s²

(d) By Newton's second law, the tension in the line is

<em>F</em> = (1.3 kg) (4.7 m/s²) ≈ 6.0627 N ≈ 6.1 N

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the average american receives 2.28 mSv dose equivalent from radon each year. Assuming you receive this dose, and it all comes fr
Dmitry [639]

Answer:

The approximate number of decays  this represent  is  N= 23*10^{10}  

Explanation:

 From the question we are told that

    The amount of Radiation received by an average american is I_a = 2.28 \ mSv

     The source of the radiation is S = 5.49 MeV \ alpha \ particle

 Generally

            1 \  J/kg = 1000 mSv

   Therefore  2.28 \ mSv = \frac{2.28}{1000} = 2.28 *10^{-3} J/kg

Also  1eV = 1.602 *10^{-19}J

  Therefore  2.28*10^{-3} \frac{J}{kg} = 2.28*10^{-3} \frac{J}{kg}  * \frac{1ev}{1.602*10^{-19} J} = 1.43*10^{16} ev/kg

           An Average american weighs 88.7 kg

      The total energy received is mathematically evaluated as

        1 kg ------> 1.423*10^{16}ev \\88.7kg  --------> x

Cross-multiplying and making x the subject

           x = 88.7 * 1.423*10^{16} eV

              x = 126.2*10^{16}eV

Therefore the total  energy  deposited is x = 126.2*10^{16}eV

The approximate number of decays  this represent  is mathematically evaluated as

            N = \frac{x}{S}

Where n is the approximate number of decay

   Substituting values

                             N = \frac{126 .2*10^{16}}{5.49*10^6}  

                                  N= 23*10^{10}  

                     

             

7 0
3 years ago
Your oven has a power rating of 5000 watt...
romanna [79]
A). 1,000 watts = 1 kilowatt
5,000 watts = 5 kilowatts

b). (5 kilowatts) x (2 hours) = 10 kilowatt-hours (kWh)

c). (10 kWh) x (15 cents/kWh) = $1.50
4 0
3 years ago
What source of energy is responsible for the water cycle
Eduardwww [97]
Water? The sun. I DUNNO I FEEL BAD :(
7 0
2 years ago
Sometimes students are taught that "air expands as it is heated". And sometimes they are taught that "as air expands it cools".
hram777 [196]

Answer:

Both are true under specific circumstances. And are related to Boyle's law. volume and pressure in a gas are inversely proportional.

Explanation:

There is a tendency to entropy in our reality, that is, in particular true and visible with gases, they tend to occupy the whole space where they are confined, when we heat a volume of gas, then the movement of the particles and in consequence the pressure of the gas increases and to compensate this the volume tends to be increased too, according to Boyle's law. And the opposite happens when the volume is increased, then the pressure is  relieved and since the particles are further one from each other, then the temperature is lower, and therefore it cools down.

7 0
3 years ago
Calculate the linear momentum for each of the following cases. (a) A proton with mass 1.67 ✕ 10-27 kg moving with a velocity of
Oliga [24]

Answer:

8.4168\times 10^{-21}\ kgm/s upward

4.725 kgm/s to the right

468.6 kgm/s southwest

1.782\times 10^{49}\ kgm/s forward

Explanation:

When the mass of an object is multiplied by its velocity we get momentum

m = Mass

v = Velocity

Proton

p=mv\\\Rightarrow p=1.67\times 10^{-27}\times 5.04\times 10^6\\\Rightarrow p=8.4168\times 10^{-21}\ kgm/s

The momentum of the proton is 8.4168\times 10^{-21}\ kgm/s upward

Bullet

p=mv\\\Rightarrow p=0.015\times 315\\\Rightarrow p=4.725\ kgm/s

The momentum of the bullet is 4.725 kgm/s to the right

Sprinter

p=mv\\\Rightarrow p=71\times 6.6\\\Rightarrow p=468.6\ kgm/s

The momentum of the sprinter is 468.6 kgm/s southwest

Earth

p=mv\\\Rightarrow p=5.98\times 10^{24}\times 2.98\times 10^4\\\Rightarrow p=1.782\times 10^{29}\ kgm/s

The momentum of the sprinter is 1.782\times 10^{29}\ kgm/s forward

4 0
3 years ago
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