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2 years ago

The location of the proton is ______ in an atom?

Physics

2 answers:

REY [17]2 years ago

4 0

Answer:

option c) nucleus

Explanation:

hope it helps ❤️

blsea [12.9K]2 years ago

3 0

Answer:

nucleus

hope this helps

have a good day :)

Explanation:

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What frequency is received by a stationary mouse just before being dispatched by a hawk flying at it at 24.7 m/s and emitting a

Montano1993 [528]

Answer:

f' = 3665.51 Hz

Explanation:

given,

speed of the hawk = 24.7 m/s

frequency of screech emitted by the hawk = 3400 Hz

speed of sound = 331 m/s

By Doppler's effect

$f' = (\dfrac{v}{v-v_s}})f$

f' is the frequency received by the mouse

v is the speed of the sound

v_s is the speed of the hawk

now,

$f' = \dfrac{341}{341-24.7}}\times 3400$

f' = 1.078 x 3400

f' = 3665.51 Hz

The frequency received by the stationary mouse is equal to 3665.51 Hz

6 0

3 years ago

What causes turbulence?

melomori [17]

Answer:

Explanation:

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6 0

3 years ago

2 examples of balanced forces

valina [46]

Answer:

<h2>Here are some examples of situations involving balanced forces. </h2><h2>Hanging objects. The forces on this hanging crate are equal in size but act in opposite directions.</h2><h2>Floating in water. Objects float in water when their weight is balanced by the upthrust from the water.</h2><h2>Standing on the ground.</h2>

I hope this helps

6 0

3 years ago

In the case of the vacuum tube and movable stopper, what force moves the stopper?

sergejj [24]

I'm pretty sure it's the<span> impact of the air molecules on the outside of the stopper. They exert a net inward force, which is not resisted by anything on the other side.</span>

6 0

3 years ago

Read 2 more answers

A convex lens of focal length 35 cm produces a magnified image 2.5 times the size of the object. What is the object distance if

Zanzabum

Answer:

Image distance is -52.5 cm

Image is virtual and forms on the same side of the lens and upright image is formed.

Explanation:

u = Object distance

v = Image distance

f = Focal length = 35

m = Magnification = 2.5

$m=-\frac{v}{u}\\\Rightarrow 2.5=-\frac{v}{u}\\\Rightarrow v=-2.5 u$

Lens equation

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{35}=\frac{1}{u}+\frac{1}{-2.5u}\\\Rightarrow \frac{1}{35}=\frac{3}{5u}\\\Rightarrow u=21\ cm$

$v=-2.5\times 21=-52.5\ cm$

Image distance is -52.5 cm

Image is virtual and forms on the same side of the lens and upright image is formed.

3 0

3 years ago