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3 years ago

5

How much heat is released to freeze 47.30 grams of copper at its freezing point of 1,085°C? The latent heat of fusion of copper

is 205.0 J/g.

2 answers:

krek1111 [17]3 years ago

4 0

the answer is -9,697

timofeeve [1]3 years ago

3 0

Answer:

9696.5 J of heat is released

Explanation:

Heat released= mass of substance× specific latent heat of fusion

= 47.3×205

= 9696.5 J

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3 years ago

A long ramp made of cast iron is sloped at a constant angle θ = 52.0∘ above the horizontal. Small blocks, each with mass 0.42 kg

dezoksy [38]

Answer:

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For copper

$h = 1.05 m$

For Lead

$h = 1.23 m$

For Zinc

$h = 2.43 m$

Explanation:

As we know that final speed of the block is calculated by work energy theorem

$W_f + W_g = \frac{1}{2}mv^2$

now we have

$-\mu_k mg cos\theta(\frac{h}{sin\theta}) + mgh = \frac{1}{2}mv^2$

now we have

$v^2 = 2gh - 2\mu_k g h cot\theta$

$v = \sqrt{2gh(1 - \mu_k cot\theta)}$

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$4 = \sqrt{2(9.81)(h)(1 - 0.15cot52)}$

$h = 0.92 m$

For copper

$4 = \sqrt{2(9.81)(h)(1 - 0.29cot52)}$

$h = 1.05 m$

For Lead

$4 = \sqrt{2(9.81)(h)(1 - 0.43cot52)}$

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3 years ago

7. An 8 kg ball is travelling to the east at 10 ms', collides with a 2 kg ball travelling to the

Ymorist [56]

Answer:

The final velocity of the ball is 7m/s

Explanation:

M1=8kg, V1 =10m/s , M2=2kg , V2=-5m/s

initial momentum before collison

m1v1+m2v2

=8×10 +2×(-5) =80-10 = 70kg m/s

final momentum after collison

=(m1+m2)×v

=(8+2)×v

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According to the law of conversion of momentum

initial momentum =final momentum

70=10v

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3 0

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