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kobusy [5.1K]
3 years ago
9

Just giving out points for no reason lol

Mathematics
2 answers:
Ronch [10]3 years ago
7 0
Thanks you alottttt. Just need those little points
Firlakuza [10]3 years ago
5 0

Answer:

Hey! Thanks a bunch!

Step-by-step explanation:

Hope you have a great day!!

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Setler79 [48]
It is 207 remainder 5
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Plot the points in the coordinate plane. Then find the perimeter and area of the polygon.
anyanavicka [17]

Answer:

The answer to your question is below

Step-by-step explanation:

See the graph below

Process

1.- Find the distance from A to B, B to C, C to D, A to D

Formula

d = \sqrt{(x2 - x1)^{2} + (y2 - y1)^{2}}

d AB = \sqrt{(1 + 3)^{2} + (6 - 5)^{2}}  = \sqrt{17}

dBC = \sqrt{(-2 -6)^{2} + (3 - 1)^{2}}  = \sqrt{68}

dCD = \sqrt{(-1 - 3)^{2} + (-3 +2)^{2}}  = \sqrt{17}

dAD = \sqrt{(-1 + 3)^{2} + (-3 - 5)^{2}}  = \sqrt{68}

2.- Find the perimeter

Perimeter = 2\sqrt{17} + 2\sqrt{68} = 6\sqrt{17} u

3.- Find the area

Area = \sqrt{17} x \sqrt{68}

Area = \sqrt{17x68} = \sqrt{1156} = 34 u^{2}

7 0
4 years ago
Laboratory experiment shows that the life of the average butterfly is normally distributed with a mean of 18.8 days and a standa
inessss [21]

Answer:

a) 0.4164

Step-by-step explanation:

Mean lifespan (μ) = 18.8 days

Standard deviation (σ) = 2 days

For any given lifespan 'X', the z-score is:

z=\frac{X- \mu}{\sigma} \\z=\frac{X- 18.8}{2}

For X=12.04 days:

z=\frac{12.04 - 18.8}{2} \\z=-3.38

A z-score of -3.38 falls in the 0.036-th percentile of a normal distribution.

For X=18.38 days:

z=\frac{18.38 - 18.8}{2} \\z=-0.21

A z-score of -3.38 falls in the 41.68th percentile of a normal distribution.

The probability that a butterfly lives between 12.04 and 18.38 days is

P=41.68-0.036\\P=41.64\%\ or\ 0.4164

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3 years ago
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Vesna [10]
C I took the test and got it right
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Solve the inequality and graph its solution: 6n – 11 > 31
miss Akunina [59]
<span>6n – 11 > 31
</span><span>6n  > 31 + 11
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  n > 42/6
  n > 7
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3 years ago
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