Question

Arrange the functions in ascending order, starting with the function that eventually has the least value and ending with the function that eventually has the greatest value.
3x + 8

4x + 3

x2 + 6

3x

4x

x2


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↓


↓


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Answer 1

Answer:

3x < 4x < 3x + 8  < 4x + 3 < x² < x² + 6

Step-by-step explanation:

This is because as x → ∞

3x → 3∞ ,

Also, as x → ∞

4x → 4∞ ,

Also, as x → ∞

3x + 8  → 3∞ + 8,

Also, as x → ∞

4x + 3 → 4∞ + 3 ,

Also, as x → ∞

x² → ∞²,

Also, as x → ∞

x² + 6 → ∞² + 6

and 3∞ < 4∞ < 3∞ + 8 < 4∞  + 3 < ∞² < ∞² + 6

Thus as x → ∞

3x < 4x < 3x + 8  < 4x + 3 < x² < x² + 6 in ascending order