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3 years ago

THIS ASSIGNMENT IS DUE BY 5! PLEASE HELP!!

Chemistry

2 answers:

hammer [34]3 years ago

5 0

Answer:

phenotypic plasticity

Explanation:

kipiarov [429]3 years ago

4 0

Answer:

its not inclusive fitness which is confusing but

Explanation:

ill give the answer when I finish the test

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The combustion of ethane (C2H6)(C2H6) produces carbon dioxide and steam. 2C2H6(g)+7O2(g)⟶4CO2(g)+6H2O(g) 2C2H6(g)+7O2(g)⟶4CO2(g)

Vera_Pavlovna [14]

Answer:

11.9 moles of carbon-dioxide will produced.

Explanation:

Given moles of ethane = 5.95 mol

$2C_2H_6(g)+7O_2(g)\rightarrow 4CO_2(g)+6H_2O(g)$

According to reaction 2 moles of ethane produces 4 moles of carbon-dioxide.

Then, 5.95 moles of ethane will produce:

$\frac{4}{2}\times 5.95 mol=11.9 mol$ of carbon-dioxide

11.9 moles of carbon-dioxide will produced.

8 0

3 years ago

A mixture of 0.307 M Cl 2 , 0.465 M F 2 , and 0.706 M ClF is enclosed in a vessel and heated to 2500 K . Cl 2 ( g ) + F 2 ( g )

monitta

Answer: The equilibrium concentration of chlorine gas, fluorine gas and ClF gas is 0.159 M, 0.317 M and 1.002 M respectively.

Explanation:

We are given:

Initial concentration of chlorine gas = 0.307 M

Initial concentration of fluorine gas = 0.465 M

Initial concentration of ClF gas = 0.706 M

The given chemical equation follows:

$Cl_2(g)+F_2(g)\rightleftharpoons 2ClF(g)$

Initial: 0.307 0.465 0.706

At eqllm: 0.307-x 0.465-x 0.706+2x

The expression of $K_c$ for above equation follows:

$K_c=\frac{[ClF]^2}{[Cl_2][F_2]}$

We are given:

$K_c=20.0$

Putting values in above equation, we get:

$20.0=\frac{(0.706+2x)^2}{(0.307-x)(0.465-x)}\\\\x=0.148,0.993$

Neglecting the value of x = 0.993 because the equilibrium concentrations of chlorine and fluorine gases will become negative, which is not possible

So, equilibrium concentration of chlorine gas = (0.307 - x) = [0.307 - 0.148] = 0.159 M

Equilibrium concentration of fluorine gas = (0.465 - x) = [0.465 - 0.148] = 0.317 M

Equilibrium concentration of ClF gas = (0.706 + 2x) = [0.706 + 2(0.148)] = 1.002 M

Hence, the equilibrium concentration of chlorine gas, fluorine gas and ClF gas is 0.159 M, 0.317 M and 1.002 M respectively.

5 0

3 years ago

Find the ph of a buffer that consists of 0.18 m ch3nh2 and 0.73 m ch3nh3cl (pkb of ch3nh2 = 3.35)?

ozzi

Hello!

First, we need to determine the pKa of the base. It can be found applying the following equation:

$pKa=14-pKb=14-3,35=10,65$

Now, we can apply the Henderson-Hasselbach's equation in the following way:

$pH=pKa+log( \frac{[CH_3NH_2]}{[CH_3NH_3Cl]} )=10,65+log( \frac{0,18M}{0,73M} )=10,04$

So, the pH of this buffer solution is 10,04

Have a nice day!

8 0

3 years ago

A bitter liquid ,ph= is classified as

choli [55]

It is a basic liquid.

Hope it helped!

8 0

3 years ago

The number of oxygen atoms in 48.0g of oxygen gas

Doss [256]

Answer:

Now u have 48 g of O2. There. Fore mole=weight/M. W. Of oxygen. Therefor 3mole.

After that if we to multiply the avogadro number with it. So 3 *NA

Now u want only atom calculation then we have 2 molecule of oxygen then multiply it with 2 too.

So final claculation is =3*2*NA.

Explanation:

your welcome

brainlest PLEASEEEEEEE!

3 0

4 years ago