2L CO gas produce 1L N2 gas
6.8L CO gas will produce 6.8/2 = 3.4L N2 gas
We know,
PV=nRT
203*20= n*0.0821*373
n=132.5 moles.
Answer:
Heat absorbed by water = 3985.26 j
Explanation:
Given data:
Mass of water = 75 g
Initial temperature = 20.0°C
Final temperature = 32.7°C
Specific heat of water = 4.184 j/g.°C
Heat absorbed by water = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 32.7°C - 20°C
ΔT = 12.7 °C
Q = 75 g ×4.184 j/g.°C ×12.7 °C
Q = 3985.26 j
Friction, conduction, and induction are all methods through which energy can be transferred.
Hope that helps.
Answer:
See below.
Explanation:
They both have 1 valency electron so will be metallic and in the same Group (Group 1) of the Periodic Table, so will have similar properties.
