Answer:
all behaved the same
Explanation:
I can't explain I'm just trying
Answer:
Option D. 30 mL.
Explanation:
Step 1:
The balanced equation for the reaction. This is given below:
HNO3 + KOH —> KNO3 + H2O
From the balanced equation above,
The mole ratio of the acid, nA = 1
The mole ratio of the base, nB = 1
Step 2:
Data obtained from the question. This include the following:
Volume of base, KOH (Vb) =.?
Molarity of base, KOH (Mb) = 0.5M
Volume of acid, HNO3 (Va) = 10mL
Molarity of acid, HNO3 (Ma) = 1.5M
Step 3:
Determination of the volume of the base, KOH needed for the reaction. This can be obtained as follow:
MaVa / MbVb = nA/nB
1.5 x 10 / 0.5 x Vb = 1
Cross multiply
0.5 x Vb = 1.5 x 10
Divide both side by 0.5
Vb = (1.5 x 10) /0.5
Vb = 30mL
Therefore, the volume of the base, KOH needed for the reaction is 30mL.
Answer:Noble gases:
are highly reactive.
react only with other gases.
do not appear in the periodic table.
are not very reactive with other elements.
Explanation:Noble gases:
are highly reactive.
react only with other gases.
do not appear in the periodic table.
are not very reactive with other elements.
For precipitation to happen, first tiny water droplets must condense on even tinier dust, salt, or smoke particles, which act as a nucleus. Water droplets may grow as a result of additional condensation of water vapor when the particles collide. If enough collisions occur to produce a droplet with a fall velocity which exceeds the cloud updraft speed, then it will fall out of the cloud as precipitation.
Answer:
1.12 moles of MgCl₂
Explanation:
Given parameters:
Mass of Mg(OH)₂ = 65g
Unknown:
Number of moles of MgCl₂ = ?
Solution:
To solve this problem, obtain a balanced reaction equation first;
Mg(OH)₂ + 2HCl → MgCl₂ + 2H₂O
From the reaction above, this is a typical neutralization process in which an acid reacts with a base to produce salt and water only.
Let's proceed; the reactant in excess is the HCl, acid. The other reactant is the Mg(OH)₂ and it must be the limiting reactant. A limiting reactant is one that is given in short supply and determines the extent of the reaction.
Find the number of moles of Mg(OH)₂;
Number of moles = 
Molar mass of Mg(OH)₂ = 24 + 2(16 + 1) = 58g/mol
Number of moles = 
= 1.12moles
The balanced reaction equation shows that;
1 mole of Mg(OH)₂ gives 1 mole of MgCl₂
1.12 mole of Mg(OH)₂ will produce 1.12 moles of MgCl₂
