Answer:
Yes, result is significant ; PVALUE < α
Step-by-step explanation:
Given :
x = 536
n = sample size = 1012
Phat = x / n = 536 / 1012 = 0.5296 = 0.53
H0 : P0 = 0.5
H1 : P0 > 0.5
Test statistic :
(Phat - P0) ÷ sqrt[(P0(1 - P0)) / n]
1-P0 = 1 - 0.5 = 0.5
(0.53 - 0.5) ÷ sqrt[(0.5*0.5)/1012]
0.03 ÷ 0.0157173
= 1.9087
Pvalue :
Using the Pvalue from test statistic :
Pvalue = 0.02815
To test if result is significant :
α = 0.05
0.02815 < 0.05
Pvalue < α ; Hence, result is significant at α=0.05; Hence, we reject H0.
Answer:
The first graph best represent the given scenario.
Step-by-step explanation:
Given that Kent walked to the bus stop, then sat and waited until the bus arrived. He rode the bus for 25 minutes, then walked the last 3 blocks to work. we have to find which graph best represent the scenario.
In the first graph, it is given The line increases for 10 minutes means the distance as well as time increases i.e Kent walked for 10 minutes then, stays horizontal for 15 minutes means no distance covered i.e stop or wait for 15 minutes. After that graph increases rapidly for another 25 minutes, that means rode the bus for 25 minutes then increases slowly for 5 minutes indicate walked to work.
The above graph best represent the scenario.
All three option is analysed by graphing which doesn't show the above given scenario.
Answer:
9
Step-by-step explanation:
.9*10=10
it's basically simple multiplication with a decimal
Answer: 72 minutes
Step-by-step explanation:
Pipe A can empty the water in 180 minutes = (180/60) =3 hours
Pipe A does 1/ 3 of the job in 1 hour.
Pipe B can empty the water in 120 minutes = (120/60) = 2 hours.
Pipe B does 1/ 2 of thejob in 1 hour.
Together they will do:
1/ 3 + 1/ 2 = 5/6
Together, both pipes will do 5/ 6 of the job in one hour.
To get the total time to completely drain the water will be:
= 60 ÷ 5/6
= 60 × 6/5
= 12 × 6
= 72 minutes
It takes 72 minutes to empty the pool.