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scoundrel [369]
3 years ago
9

How did James West impact their field? How would things be different in science today if James West had not accomplished what th

ey did?

Chemistry
1 answer:
VikaD [51]3 years ago
3 0

Hey~ Hope this helps!

{p.s this is hand-written not copied and pasted. Use freely}

Answer:

James West impacted his field in an abundance of ways. For example, West and Sessler are credited as the inventors of the “foil electret microphone”. Without the creation of this compact microphone over 90 percent of all contemporary microphones – which includes those found in telephones, tape records, baby monitors and hearing aids would cease to exist today.

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Which experimental feature of the MALDI-MS technique allows the separation of ions formed after the adduction of tissue molecule
34kurt

Answer:

The experimental feature of the MALDI-MS technique which allows the separation of ions formed after the adduction of tissue molecules:

B) Velocity of ions depends on the ion mass-to-charge ratio.

Explanation:

  • The option a is not correct as distance traveled by ions doesn't depend upon the ion charge rather it depends upon time for which you leave the sample to run.
  • The  option b is correct as velocity of ions depends on the ion mass-to-charge ratio because separation is done due to mass to charge ratio feature.
  • The option c is incorrect as time of travel is not inversely proportional to the ion-to-mass ratio because the ion will move across the gel until you stop the electric field.
  • The option d is not correct as electric field between MALDI plate and MS analyzer is though uniform but this feature doesn't allow the separation of ions.

6 0
3 years ago
14. Would you expect each of the following atoms to gain or lose electrons when forming ions ? what ion is the most likely in ea
yanalaym [24]

Answer:

The answer to your question is below

Explanation:

Metals lose electrons and Nonmetals gain them.

a. Ra is in group IIA it will lose electrons, the ion will be Ra⁺²

b. Br is in group VIIA it will gain electrons, the ion will be Br⁻¹

c. In is in group IIIA it will lose electrons, the ion will be In⁺³

d. Te is in group VIA it will gain electrons, the ion will be Te⁻²

e. Ca is in group IIA it will lose electrons, the ion will be Ca⁺²

f. As is in group VA it will gain electrons, the ion will be As⁻³

g. Al is in group IIlA it will lose electrons, the ion will be Al⁺³

h. Rb is in group IA it will lose electrons, the ion will be Rb⁺¹

7 0
3 years ago
Which buffer would be better able to hold a steady pH on the addition of strong acid, buffer 1 or buffer 2? Explain. Buffer 1: a
Talja [164]

Answer:

Buffer 1.

Explanation:

Ammonia is a weak base. It acts like a Bronsted-Lowry Base when it reacts with hydrogen ions.

\rm NH_3\; (aq) + H^{+}\; (aq) \to {NH_4}^{+}\; (aq).

\rm NH_3 gains one hydrogen ion to produce the ammonium ion \rm {NH_4}^{+}. In other words, \rm {NH_4}^{+} is the conjugate acid of the weak base \rm NH_3.

Both buffer 1 and 2 include

  • the weak base ammonia \rm NH_3, and
  • the conjugate acid of the weak base \rm {NH_4}^{+}.

The ammonia \rm NH_3 in the solution will react with hydrogen ions as they are added to the solution:

\rm NH_3\; (aq) + H^{+}\; (aq) \to {NH_4}^{+}\; (aq).

There are more \rm NH_3 in the buffer 1 than in buffer 2. It will take more strong acid to react with the majority of \rm NH_3 in the solution. Conversely, the pH of buffer 1 will be more steady than that in buffer 2 when the same amount of acid has been added.

5 0
4 years ago
What chemical compound is crucial to marine life and how is it disappearing?
daser333 [38]
Nitrogen is crucial to the marine life and it is disappearing because it cannot be assimilated by most organisms in the water.
5 0
3 years ago
What mass of sodium chloride contains 4.59 x 10 24 formula units?
shtirl [24]
The term formula units means molecules.

Then, what you are looking for is the mass in 4.59*10^24  molecules.

The procedure involves to convert the 4.59 * 10^24 molecules into moles and use the molar mass of the sodium chloride.

1) Number of moles = 4.59 * 10^24 molecules / (6.02 * 10^23 molecules/mol) = 7.62 mol

2) Molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol

3) mass of NaCl = molar mass *  number of moles = 58.44 g/mol * 7.62 mol = 445.31 g of NaCl

Answer: 445.31 g of NaCl.

 
7 0
3 years ago
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