For this case we have the following equation:
h = -16t2 + 32t + 6
Deriving we have:
h '= -32t + 32
Equaling to zero:
-32t + 32 = 0
We clear the time:
t = 32/32
t = 1 s
We are now looking for the maximum height:
h (1) = -16 * (1) ^ 2 + 32 * (1) + 6
h (1) = 22 feet
Answer:
The ball reaches its maximum height in:
t = 1 s
The ball's maximum height is:
h (1) = 22 feet
option: 22 ft, 1 s
Answer:
16+24=40
Step-by-step explanation: 2x+5(y-1) when x=8 and y=5. put x where it belongs, by the 2 and do the same with y, by the -1. and then slove. 2*8= 16 , 5*5= 25-1, then add 16 and 24 together and get 40.
Answer:
B
Step-by-step explanation:
17*
Answer:
Okay, gimme a sec...
Step-by-step explanation:
