Answer:
he just shrugged and *sigh*
Step-by-step explanation:
Answer
180
if your feeling nice can you give me a brainlest :)
Answer:
the amswer is c
Step-by-step explanation:
Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60

t=1
9. 9.37, 9.3, 9.219, 9.129
10. 0.101, 0.100, 0.012, 0.001
11. 5.312, 5.231, 5.132, 5.123
12. 62.950, 62.905, 62.833, 62.383
Hope it helps