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Lerok [7]
3 years ago
7

Plssss hurrryyyyyy and answerrrrrrrrrr it's due by tonight!!!!!!!! I will give brainliest​

Mathematics
1 answer:
Sholpan [36]3 years ago
6 0

Answer:

Line m

Step-by-step explanation:

The points are ranged from the region of ages 2-12. These points are aligned and near Line m.

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A health statistics agency in a certain country tracks the number of adults who have health insurance. Suppose according to the
Nana76 [90]

Answer:

a) There is a 15.3% probability that a randomly selected person in this country is 65 or older.

b) Given that a person in this country is uninsured, there is a 2.2% probability that the person is 65 or older.

Step-by-step explanation:

We have these following percentages:

5.3% of those under the age of 18, 12.6% of those ages 18–64, and 1.3% of those 65 and older do not have health insurance.

22.6% of people in the county are under age 18, and 62.1% are ages 18–64.

(a) What is the probability that a randomly selected person in this country is 65 or older?

22.6% are under 18

62.10% are 18-64

The rest are above 65

So

100% - (22.6% + 62.10%) = 15.3%

There is a 15.3% probability that a randomly selected person in this country is 65 or older.

b) Given that a person in this country is uninsured, what is the probability that the person is 65 or older?

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

So, what is the probability that a person is 65 and older, given that the person is uninsured.

P(B) is the probability that a person is 65 and older. From a), we have that P(B) = 0.153

P(A/B) is the probability is uninsured, given that that person is 65 and older. So P(A/B) = 0.013

P(A) is the probability that a person is uninsured. That is the sum of 5.3% of 22.6%, 12.6% of 62.1% and 1.3% of 15.3%. So:

P(A) = 0.053*(0.226) + 0.126*(0.621) + 0.013*(0.153) = 0.0922

So

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.153*0.013}{0.0922} = 0.022

Given that a person in this country is uninsured, there is a 2.2% probability that the person is 65 or older.

6 0
2 years ago
1/4 of a number minus 8 is -23
Bas_tet [7]

Answer:

I have solved it u can have a look.

6 0
3 years ago
Karen has 7 over 8cup of ice cream. How many 1 over 3cup servings can she make?
AlexFokin [52]
First, we need to find the least common denominator. The LCD for 7/8 and 1/3 would be 24. 7*3/8*3 = 21/24. 1*8/3*8 = 8/24. So, how many 8/24 will go into 21/24? 8 goes into 21 two times, and we are left with a remainder of 5. The answer is: Karen can make 2 and 1/24 servings of 1/3 cups of ice cream.
3 0
3 years ago
Read 2 more answers
A random sample of bolts is taken from inventory, and their lengths are measured. The average length in the sample is 5.3 inches
LekaFEV [45]

Answer:

L_x=5.3 inches

Step-by-step explanation:

Average length \=x =5.3 inches

Standard deviation \sigma=0.2 inches

Sample size n=50

Generally The point estimate for the mean length of all bolts in inventory is

L_x= \=x

L_x=5.3 inches

3 0
3 years ago
Complete the equation: x^2+8x + _=(_)^2
pentagon [3]

Answer:

x^2+8x+<u>1</u><u>6</u><u>=</u><u>(</u><u>x-4</u><u>)</u><u>^</u><u>2</u>

<em><u>EXPLANATION</u></em><em><u>:</u></em>

<u>(</u><u>a</u><u>+</u><u>b</u><u>)</u><u>^</u><u>2</u><u>=</u><u>a2</u><u>+</u><u>2</u><u>.</u><u>a</u><u>.</u><u>b</u><u>+</u><u>b2</u>

<u>we</u><u> </u><u>have</u><u> </u><u>to</u><u> </u><u>break</u><u> </u><u>the</u><u> </u><u>middle</u><u> </u><u>term</u><u> </u><u>i</u><u>n</u><u> </u><u>2</u><u>a</u><u>b</u><u> </u><u>here</u><u> </u><u>a</u><u> </u><u>is</u><u> </u><u>x</u><u> </u><u>then</u><u> </u><u>2</u><u>x</u><u>b</u><u>=</u><u>8</u><u>x</u><u>,</u><u> </u><u>=</u><u>></u><u> </u><u>b</u><u>=</u><u>4</u><u>,</u><u> </u><u>but</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>and</u><u> </u><u>b</u><u> </u><u>to</u><u> </u><u>get</u><u> </u><u>the</u><u> </u><u>req</u><u>uired</u><u> </u><u>equation</u><u>!</u>

8 0
3 years ago
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