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Ber [7]
3 years ago
5

What is the value of (2/4)^-4?

Mathematics
1 answer:
Maru [420]3 years ago
6 0

Answer:

16 b plus a is mathematically plus 185 so 15

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Find the zeros of y = x2 – 6x – 4 by completing the square.
katrin [286]

Answer:

The solutions to the quadratic equations are:

x=\sqrt{13}+3,\:x=-\sqrt{13}+3

Step-by-step explanation:

Given the function

y\:=\:x^2\:-\:6x\:-\:4

substitute y = 0 in the equation to determine the zeros

0\:=\:x^2\:-\:6x\:-\:4

Switch sides

x^2-6x-4=0

Add 4 to both sides

x^2-6x-4+4=0+4

Simplify

x^2-6x=4

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2

x^2-6x+\left(-3\right)^2=13

Apply perfect square formula:  (a-b)² = a²-2ab+b²

\left(x-3\right)^2=13

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solve

x-3=\sqrt{13}

Add 3 to both sides

x-3+3=\sqrt{13}+3

Simplify

x=\sqrt{13}+3

now solving

x-3=-\sqrt{13}

Add 3 to both sides

x-3+3=-\sqrt{13}+3

Simplify

x=-\sqrt{13}+3

Thus, the solutions to the quadratic equations are:

x=\sqrt{13}+3,\:x=-\sqrt{13}+3

4 0
3 years ago
Factor the expression.<br> 10x + 25<br> (Factor completely.)
Luda [366]

Answer:

5(2x+5)

Step-by-step explanation:

This is the answer because the highest multiple is 5 for both of them.

so since it is 5 divide both numbers by 5 put 5 outside the parenthisis  and

then divide the numbers inside

this will give you - 5(2x+5)

Hope it helps :)

8 0
3 years ago
Read 2 more answers
I need help for these problems!!! Thanks!
Triss [41]
I do before but your questions a bit wired seems like they already help u solve ?
8 0
4 years ago
I need help someone help me out please
Alekssandra [29.7K]

Answer:

(multiple)

Step-by-step explanation:

it says 2,0 which 2 is the bottom line. You go to 2 at the bottom then go up to 0. Therefore, 2 is C. Start on the bottom, and move your finger up until you hit the second number. Right in the middle of that is your answer. Hope this helps! :)

3 0
3 years ago
HELP PLEASE !!!!
Ede4ka [16]
What was the price in the the first time
3 0
3 years ago
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